Answer:
Strong acids are assumed 100% dissociated in water- True
As a solution becomes more basic, the pOH of the solution increases- false
The conjugate base of a weak acid is a strong base- true
The Ka equilibrium constant always refers to the reaction of an acid with water to produce the conjugate base of the acid and the hydronium ion- True
As the Kb value for a base increases, base strength increases- true
The weaker the acid, the stronger the conjugate base- true
Explanation:
An acid is regarded as a strong acid if it attains 100% or complete dissociation in water.
The pOH decreases as a solution becomes more basic (as OH^- concentration increases).
Ka refers to the dissociation of an acid HA into H3O^+ and A^-.
The greater the base dissociation constant, the greater the base strength.
The weaker an acid is, the stronger , its conjugate base will be.
Answer:
true
Explanation: becuase if you add the same liquid to a small container and then add it to a big container its going to have the same liquid amount it started with
Answer:
since that's the closest option we have
10.6atm
Explanation:
Since volume is constant
P1/T1 = P2/T1
P1 =8.5atm
T1 = 59.2°C = 332.2k
T2 = 140°C = 413k
P2 = ?
8.5/332.2 = P2/413
0.026 = P2/413
P2 = 0.026 x 413
P2 = 10.74atm
Answer:
depending on how you change the angle on the ramp the kanetic energy can go up or down depending on how u angle the ramp
Explanation:
We have to know how flame colour can be used to identify the metal ion in an unknown compound.
If golden yellow coloured flame , then Na⁺ ion because electrons get excited on heating and again fall back to emit energy of definite wavelengths corresponding to particular colour in the visible region.
If violet coloured flame , then K⁺ because electrons get excited on heating and again fall back to emit energy of definite wavelengths corresponding to particular colour in the visible region.
If crimson red coloured flame , then Sr²⁺ because electrons get excited on heating and again fall back to emit energy of definite wavelengths corresponding to particular colour in the visible region.
If yellowish green coloured flame , then Ba²⁺ because electrons get excited on heating and again fall back to emit energy of definite wavelengths corresponding to particular colour in the visible region.
