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Katyanochek1 [597]
3 years ago
11

what is the specific heat of a substance if 300 j are required to raise the temperature of a 267-g sample by 12 degrees c

Chemistry
1 answer:
slava [35]3 years ago
3 0

Answer : The specific heat of the substance is 0.0936 J/g °C

Explanation :

The amount of heat Q can be calculated using following formula.

Q = m \times C \times \bigtriangleup T

Where Q is the amount of heat required = 300 J

m is the mass of the substance = 267 g

ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

C = \frac{Q}{m \times \bigtriangleup T}

Let us plug in the values in above equation.

C = \frac{300J}{267g \times 12 C}

C = \frac{300J}{3204 g C}

C = 0.0936 J/g °C

The specific heat of the substance is 0.0936 J/g°C

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Answer:

<h3>The answer is 2.50 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

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From the question

mass = 25 g

volume = 10 mL

We have

density =  \frac{25}{10}  =  \frac{5}{2}  \\

We have the final answer as

<h3>2.50 g/mL</h3>

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The forth quantum number is Spin quantum number and the value of Spin Quantum Number of 1s² will be +1/2. Therefore, the correct option is (B) option

<h3>What is Spin Quantum Number ?</h3>

It describes the orientation of the electron spin (rotation) in space.

In the given case of 1s² configuration,

since, the Quantum numbers are known as:

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       The allowed values of n are therefore 1, 2, 3, 4, and so on.

  • Angular quantum number (l) is able to be any integer between 0  

       and n-1.

       Therefore, for example, If n = 1, l will be 0,

                                                If n = 2, l can be either 0 or 1.

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Learn more about Quantum Number Here ;

brainly.com/question/15325270

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