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Nady [450]
3 years ago
11

What type of compound does the formula, Fe2O3, represent ?

Chemistry
1 answer:
seraphim [82]3 years ago
8 0

It is:
Iron (III) Oxide

As a transition metal iron can have two oxidation states <span>F<span>e+</span>2</span> ferrous or <span>F<span>e+</span>3</span>ferric.

Oxygen has an oxidation state of <span>O<span>−2</span></span>.

In the case of <span>F<span>e2</span><span>O3</span></span> the oxidation states are balanced when 2 <span>F<span>e<span>+3</span></span></span> ions pair with 3 <span>O<span>−2</span></span>.

<span>F<span>e2</span><span>O3</span></span> is Iron (III) oxide where the roman numeral informs us that the charge on the iron is +3, the common name would be ferric oxide.

If the iron was <span>F<span>e<span>+2</span></span></span> and the oxygen <span>O<span>−2</span></span>, the formula would be FeO Iron (II) oxide or ferrous oxide.

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Based on the octet rule, nitrogen most likely forms a __ion.
Greeley [361]

Answer:

b) N3-

Explanation:

The octet rule stipulates that a chemical specie is stable if it has eight electrons in its outermost shell.

Nitrogen belongs to group 15. This means that it has five electrons in its outermost shell. The formation  N3- means that it accepted three electrons.

This brings the total number of outermost electrons to eight in accordance with the octet rule.

4 0
3 years ago
Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
What is the buoyant force of a dog that displaces 10 pounds of water?
Troyanec [42]

Answer:

pls answer this link for the answer :D

Explanation:

brainly.com/question/22200936

5 0
3 years ago
Calculate the number of mg of Allura Red present in an 10 fluid ounce glass of the beverage you used in this lab. Assume that th
il63 [147K]

Answer : The mass of Allura Red present in an 10 fluid ounce glass of the beverage is, 7.634 mg.

Explanation : Given,

Volume of solution = 10 fl oz = 295.735 mL

Molar mass of Allura Red = 496.42 g/mole

Concentration of Allura Red (Molarity) = 0.000052 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of Allura Red}\times 1000}{\text{Molar mass of Allura Red}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

0.000052M=\frac{\text{Mass of Allura Red}\times 1000}{496.42g/mole\times 295.735mL}

\text{Mass of Allura Red}=0.007634g=7.634mg

Therefore, the mass of Allura Red present in an 10 fluid ounce glass of the beverage is, 7.634 mg.

5 0
3 years ago
Chemistry problem H=WQx solve for x
Lana71 [14]
You just have to isolate x, so just divide by WQ on both sides to get:
x =  \frac{H}{WQ}
8 0
3 years ago
Read 2 more answers
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