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Fudgin [204]
3 years ago
11

What is the length of the second base of a trapezoid if the length of one base is 27 and the length of the mid-segment is 19? sh

ow your work
Mathematics
2 answers:
madreJ [45]3 years ago
8 0
The length of <span>the second base of a trapezoid if the length of one base is 27 and the length of the mid-segment is 19 is that it is 11.

</span>Solution:

Length of the mid-segment = (long base + short base) / 219
 = (27 + short base) / 219 - (27 / 2)
= short base / 2 times 238 -27
= short baseshort base
 = 11
stira [4]3 years ago
3 0
Length of the mid-segment = (long base + short base) / 219 = (27 + short base) / 219 - (27 / 2) = short base / 2Multiplying both sides by 238 -27 = short baseshort base = 11
Source:http://www.1728.org/quadtrap.htm


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sp2606 [1]

Answer: (2x - 5) • (4x - 1)

STEP 1 : Equation at the end of step 1

(23x2 - 22x) + 5

STEP 2 : Trying to factor by splitting the middle term

2.1 Factoring 8x2-22x+5

The first term is, 8x2 its coefficient is 8 .

The middle term is, -22x its coefficient is -22 .

The last term, "the constant", is +5

Step-1 : Multiply the coefficient of the first term by the constant 8 • 5 = 40

Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -22 .

-40 + -1 = -41

-20 + -2 = -22 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -20 and -2

8x2 - 20x - 2x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

4x • (2x-5)

Add up the last 2 terms, pulling out common factors :

1 • (2x-5)

Step-5 : Add up the four terms of step 4 :

(4x-1) • (2x-5)

Which is the desired factorization

Final result : (2x - 5) • (4x - 1)

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