Answer:
E(X) = 6
Var(X) = 3.394
Step-by-step explanation:
Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each
of the (100, 20) ways to catch the 20 fishes will be equally likely.
Thus, we can say that X fulfills a hypergeometric
distribution with parameters as follows;
n = 20, N = 100, k = 30
Formula for expected mean value in hypergeometric distribution is;
E(X) = nk/N
E(X) = (20 × 30)/100
E(X) = 6
Formula for variance is;
Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]
Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]
Var(X) = 6 × 0.5657
Var(X) = 3.394
Answer:
- T'(1, -2)
- U'(1, -1)
- V'(2, -1)
- W'(2,-2)
Step-by-step explanation:
Translation 4 right adds 4 to each x-coordinate.
Translation 4 down subtracts 4 from each y-coordinate.
Doing this arithmetic gives you the results above.
Answer:
The equation of the circle can be written as:
Step-by-step explanation:
The general equation of a circle with center 
and radius 
is:
In our example, we know 
, as we just have to make sure we need determine 
.
As the circle passes through (10, 14), that pair of values for x and y must satisfy the equation. So we have:
Thus the equation of the circle can be written as:
Answer:
16
Step-by-step explanation:
I JUST TOOK THE TEST YW
Answer:
Use quickmath.com
or
You can use photo math to get the answer
