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sertanlavr [38]

3 years ago

14

Valentina purchased 200 beads for $48 to make necklaces. If she needs to buy 25 more beads, how much will she pay if she is char

ged the same rate?

1 answer:

meriva3 years ago

5 0

$\frac{200}{48} = \frac{25}{x} \\ \\ 200x=48 (25) \\ \\ 200x =1200 \\ \\ \boxed {x=6}$

It would cost her $6

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What is 14 52/60 simplified to

Flauer [41]

Remember that mixed fractions are equivalent to the sum of the whole number and the fraction. Thus, we can start by simplifying the mixed fraction like so:

$14 \dfrac{52}{60} = 14 + \dfrac{52}{60} = \dfrac{892}{60} Now, realize that both 892 and 60 have a common factor of 4, which means that we can divide both the numerator and the denominator by 4. This gives us:[tex]\dfrac{892 \div 4 }{60 \div 4} = \dfrac{223}{15}$

Thus, 14 52/60 simplifies to 223/15.

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3 years ago

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D) (4 radical din 2 - radical din 2 ) × radical 2 + radical 2 × radical 18

olga_2 [115]

D. (4√(2) - √(2)) × √(2) + (2) × √(18)
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6 + 12
18

E. √(3) × (2√(5) + 3√(5)) - √(5) × (√(3) + 2√(3))
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3 years ago

What is the true solution to the equation below?

Marina CMI [18]

Answer:

The solution is:

$x=4$

Step-by-step explanation:

Considering the expression

$lne^{lnx}+lne^{lnx}^{^2}=2ln8$

$\ln \left(e^{\ln \left(x\right)}\right)+\ln \left(e^{\ln \left(x\right)\cdot \:2}\right)=2\ln \left(8\right)$

$\mathrm{Apply\:log\:rule}:\quad \:log_a\left(a^b\right)=b$

$\ln \left(e^{\ln \left(x\right)}\right)=\ln \left(x\right),\:\space\ln \left(e^{\ln \left(x\right)2}\right)=\ln \left(x\right)2$

$\ln \left(x\right)+\ln \left(x\right)\cdot \:2=2\ln \left(8\right)$

$\mathrm{Add\:similar\:elements:}\:\ln \left(x\right)+2\ln \left(x\right)=3\ln \left(x\right)$

$3\ln \left(x\right)=2\ln \left(8\right)$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3\ln \left(x\right)}{3}=\frac{2\ln \left(8\right)}{3}$

$\ln \left(x\right)=\frac{2\ln \left(8\right)}{3}.....A$

Solving the right side of the equation A.

$\frac{2\ln \left(8\right)}{3}$

As

$\ln \left(8\right):\quad 3\ln \left(2\right)$

Because

$\ln \left(8\right)$

$\mathrm{Rewrite\:}8\mathrm{\:in\:power-base\:form:}\quad 8=2^3$

⇒ $\ln \left(2^3\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(2^3\right)=3\ln \left(2\right)$

So

$\frac{2\ln \left(8\right)}{3}=\frac{2\cdot \:3\ln \left(2\right)}{3}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6$

$=\frac{6\ln \left(2\right)}{3}$

$\mathrm{Divide\:the\:numbers:}\:\frac{6}{3}=2$

$=2\ln \left(2\right)$

So, equation A becomes

$\ln \left(x\right)=2\ln \left(2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$=\ln \left(2^2\right)$

$=\ln \left(4\right)$

$\ln \left(x\right)=\ln \left(4\right)$

$\mathrm{Apply\:log\:rule:\:\:If}\:\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\:\mathrm{then}\:f\left(x\right)=g\left(x\right)$

$x=4$

Therefore, the solution is

$x=4$

6 0

3 years ago

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Elena-2011 [213]

Answer: both of you have a lead yet but you can get it right away if I can see you guys again in a developer way but I have a game pass

Step-by-step explanation: yes

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3 years ago

Directions: Using trig functions, find the value of each variable. Write your final answer

sergey [27]

$\bold{ANSWER:}$

x = 5.4

$\bold{EXPLANATIONS:}$

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3 years ago