4.6to the twelth power plus ten or something like that it has been a while since I have done the scientific notation but where ever you put in the number of zeros. is twelve

6 0

3 years ago

A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of

mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.125

t = ?

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.125=e^{-0.00440\times t}$

t = 473 year

8 0

3 years ago

Consider the titration of 30.0 mL of 0.200 M HClO4 with 0.100 M KOH. Calculate the pH of the resulting solution after the follow

Umnica [9.8K]

Answer:

xxfbhg CV ccdfg CD did ffg bgg exvgex

8 0

3 years ago

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Phoenix [80]

Answer: Option (B) is the correct answer.

Explanation:

It is known that for writing a chemical reaction equation, reactants are written on left hand side whereas products are written on right hand side.

And in between reactants and products a forward arrow is placed pointing towards the products.

Therefore, the reaction for carbon burns in the presence of oxygen to give carbon dioxide will be written as follows.

$Carbon + Oxygen \rightarrow Carbon dioxide$

Here, carbon and oxygen atoms are the reactants whereas carbon dioxide is the product.

6 0

3 years ago