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Alekssandra [29.7K]
4 years ago
9

HELP PLS kakwkwkwkkwkwkw

Chemistry
1 answer:
Vanyuwa [196]4 years ago
4 0

Answer:

yo try and search it on Google

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what do the symbols tell you about the conditions of the reaction shown to the right check all boxes that apply
alukav5142 [94]

Answer:

Sorry but erm was their supposed to be a image attach with it

Explanation:

6 0
3 years ago
Read 2 more answers
Which orbital is partially filled in the Zirconium (ZI) atom?
Nikolay [14]

Answer:

4d orbital.

Explanation:

Hello!

In this case, since zirconium's atomic number is 40, we fill in the electron configuration up to 40 as shown below:

1s^2,2s^2,2p^6, 3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^2

Thus, the orbital 4d is partially filled.

Best regards!

3 0
3 years ago
A chemist prepares a solution of silver(I) nitrate by measuring out of silver(I) nitrate into a volumetric flask and filling the
leva [86]

Answer:

3.33 M

Explanation:

It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:

" <em>A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.</em>

<em>Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits.</em> "

In this case, first we <u>calculate the moles of AgNO₃</u>, using its molecular weight:

  • 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃

Then we<u> convert the 150 mL of the volumetric flask into L</u>:

  • 150 / 1000 = 0.150 L

Finally we <u>divide the moles by the volume</u>:

  • 0.500 mol AgNO₃ / 0.150 L = 3.33 M
4 0
3 years ago
How do you solve this
3241004551 [841]
With your mind. Boom. Lol I'm sorry I don't know I just need points
4 0
3 years ago
Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
Vilka [71]

Answer:

147.2g

Explanation:

The full solution can be found in the image attached. Graham's law was applied to the problem. The rate of diffusion of a gas is inversely proportional to its molar mass or vapour density. Molar mass= 2vapour density

8 0
3 years ago
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