How is a calculation of net worth different from a day-to-day or month-to-month tallying of expenses?

1 answer:

8 0

The difference in tallying of expenses from a day to day and month to month is the consistency. in a day to day basis it is consistent the time for a day is 24 hrs it will not change, so you will really know why the expenses goes up or down/ unlike for a month to month it is inconsistent,, some months have 30, 31 or 28 days in a month.

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klio [65]

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4 0

3 years ago

(-5+2)•(-1/2)<br><br> I don’t know how to do this problem. Would anyone be able to assist? Thanks!

SpyIntel [72]

Answer:

3/2 or 1 1/2 or 1.5

Step-by-step explanation:

first do the equations in each parentheses:

(-5+2) = -3

(-1/2) = -1/2

then multiply both sides:

-3 • -1/2 (which is the same as -3 • -1 over 2)

= 3/2 or 1 1/2 or 1.5

7 0

3 years ago

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olasank [31]

Answer:

Step-by-step explanation:

5 0

3 years ago

Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$