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prisoha [69]
3 years ago
9

What s the difference btn 85,17,19,4 &2

Mathematics
1 answer:
bija089 [108]3 years ago
6 0
The difference between them is 43. :) Hope this helped!
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Simplify (6x2 − 3 − 5x3) − (4x3 2x2 − 8). 9x3 − 4x2 − 5 −9x3 4x2 5 x3 − x2 − 13x3 −x3 x2 13x3.
Schach [20]

Like terms have the same variable and power. The simplification of the expression (6x²-3-5x³)-(4x³+2x²-8) is -9x³+4x²+5.

<h3>What are Like terms?</h3>

Like terms are those terms that are having the same variables, also the variables are of the same order as well.

for example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.

We know that to simplify an expression we need to add or subtract like terms, therefore,

(6x^2- 3 - 5x^3) -(4x^3+2x^2 - 8)\\\\= 6x^2- 3 - 5x^3 -4x^3-2x^2 + 8\\\\= - 5x^3 -4x^3+6x^2-2x^2+8-3\\\\ = -9x^3+4x^2+5

Hence, the simplification of the expression (6x²-3-5x³)-(4x³+2x²-8) is -9x³+4x²+5.

Learn more about Like Terms:

brainly.com/question/2513478

7 0
2 years ago
Which strategy best explains how to solve this problem?
Rufina [12.5K]
This is a geometric sequence because each term is twice the value of the previous term.  So this is what would be called the common ratio, which in this case is 2.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1)  so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r)  where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so 

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.
4 0
3 years ago
Read 2 more answers
If carpet cost $8 per square foot. How much money will it cost to put new carpet in all the rooms in the house?
Stolb23 [73]
How many feet is the room
6 0
3 years ago
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

4 0
3 years ago
WILL MARK YOU BRAINLIEST HURRY PLZ IM ON A TIME LIMIT
alexdok [17]

Answer:

9

Step-by-step explanation:

according to the question

27×⅓

9

7 0
2 years ago
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