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vovikov84 [41]
3 years ago
13

(2k 3 +6k+1)−(2k 2 +1). Simplify and put into standard form

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

2k^3-2k^2+6k.

Step-by-step explanation:

We have been given an expression and we are asked to simplify our given expression.

(2k^3+6k+1)-(2k^2+1)

Using order of operations (PEMDAS) we will remove parenthesis first.

After removing parenthesis our expression will be,

2k^3+6k+1-2k^2-1

After canceling out 1 with -1 we will get,

2k^3+6k-2k^2

So our given expression simplifies to 2k^3+6k-2k^2.

Let us write our expression in standard form. Since our expression is a polynomial and to write any polynomial in standard form,  we write each term in order of degree, from highest to lowest, left to right.

Upon putting our polynomial into standard form we will get,

2k^3-2k^2+6k

Therefore, after simplifying and putting our given expression in standard form we get our final expression as: 2k^3-2k^2+6k.

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Hilda was simplifying some numerical expressions and made each of the following sequences of calculations. Name the mathematical
Galina-37 [17]

Answer:

Problem 1:

5 · (−4/3) · (2/5)

= (−4/3) · 5 · (2/5)   <em>Conmutative Property of Multiplication</em>

= (−4/3) · (5 · (2/5))  <em>Associative Property of Multiplication</em>

= (−4/3) · (2/1) = −8/3 = −2*2/3<em> Multiplied fractions and extracted common factor</em>

Problem 2:

17 + 29 + 3+ 1

= 17 + 3 + 29 + 1  <em>Conmutative Property of Addition</em>

= (17 + 3) + (29 + 1)  <em>Associative Property of Addition</em>

= 20 + 30 Added groups

= 50 Added terms

Step-by-step explanation:

<u>For the Problem 1:</u>

In the first step, Hilda applied the <em>Conmutative Property of Multiplication</em>, because she changed the order of the numbers in the product

In the second step, she applied the <em>Associative Property of Multiplication, </em>because she agrouped the product of 5 and<em> </em>2/5 to perform it sepparately

In the third step, she calculated<em> the product of the fractions</em> -4/3 and 2/1, then she extracted 2 as a <em>common factor</em> to express the fraction as -2*2/3

<u>For the Problem 2:</u>

In the first step, Hilda applied the <em>Conmutative Property of Addition, </em>because she changed the order of the numbers in the sum

In the second step, she applied the<em> Associative Property of Addition, </em>because she associated the addition of 17 and 3 and the addition of 29 and 1, to calculate them in groups.

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4 0
3 years ago
Read 2 more answers
3.f(-4)-3.g(-2) please help me with this problem
seraphim [82]
Question:
3.f(-4)-3.g(-2) please help me with this problem

Answer:
-12f + 6g

Step by step explanation:

8 0
3 years ago
You and your friend have agreed to do a job which pays $200 total. If you and your friend together complete 1/4 of the overall j
butalik [34]

Answer:

If you and your friend are splitting a 200 dollar job, the answer would be 25$

Step-by-step explanation:

So, divide 200 by 4

You will get 50

Then divide 50 by 2

This gives you the answer of 25

So each friend will get 25 dollars for completing 1/4th of the job

Hope this is correct and helps!

5 0
3 years ago
Read 2 more answers
How do you find the volume of spheres?
garik1379 [7]
So if u were to use a calculator, which you probably might need, you would take the radius, square it by 3, multiply by 4 and then divide by 3.
8 0
3 years ago
If p stays constant and u is doubled what happens to e? given U=EP
Stolb23 [73]

We are given the expression:

U = E * P

 

The equality symbol “ = “ means that for all cases, the value of U and E * P must always be equal. This means that whatever happens on the left side, must equally happen on the right side.

 

So what this actually means is that, if we double U so we must also double the expression E * P, that is:

2 U = 2 (E * P)

 

However since P stays constant in the process, therefore only E is changed, hence:

2 U = P * 2 E

 

So we can see that E is also doubled.

4 0
4 years ago
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