All categories

4 years ago

From the data table given, calculate the missing quantity

Chemistry

1 answer:

ololo11 [35]4 years ago

4 0

<u>Answer:</u> The initial volume of the gas is 16.55 mL

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=?mL\\T_1=300K\\V_2=16mL\\T_2=290K$

Putting values in above equation, we get:

$\frac{V_1}{300K}=\frac{16mL}{290K}\\\\V_1=\frac{16\times 300}{290}=16.55mL$

Hence, the initial volume of the gas is 16.55 mL

You might be interested in

2. Arnie is going to dissolve 2.65g of zinc using 6.0M hydrochloric acid. A) what volume of the acid will he need to dissolve al

fenix001 [56]

Answer:

Explanation:

Zn + 2HCl = ZnCl₂ + H₂

A ) mole of Zn = 2.65 / 65

= .04 mol

mole of HCl required = .04 x 2 mol

.08 mol

If v be the volume required

v x 6 = .08

v = .0133 liter

= 13.3 cc

B )

volume of gas at NTP :

moles of gas obtained = .04 moles

= 22.4 x .04 liter

= .896 liter

we have to find this volume at given temperature and pressure

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

$\frac{760\times.896}{273} =\frac{628\times V_2}{296}$

$V_2$ = 1.175 liter.

C )

.04 mole of zinc chloride will be produced

mol weight of zinc chloride

= 65 + 35.5 x 2

= 136 gm

.04 mole = 136 x .04

= 5.44 gm

5 0

3 years ago

how do i word a formal letter to a teacher saying i didn't pay attention during the science lessons and i now have no idea what

Allushta [10]

Explanation:

Hello mr/mrs (name) I unfortunately couldn't pay attention to the class due to some issues I had therefore I don't know what we are doing in class

Hello mr/mrs (name) I could understand what we were doing in class I would like it if you could break it down more or explain better to me

OR just say something it had something to do with your internet such as

Hello mr/mrs (name) I didn't understand what you were saying during our class due to some of my internet issues I was have throughout the day. I hope you can explain what we did during the class.

Those may be some of my excuses I've used before

they have worked for me:)

I don't know if that helped?:/

8 0

3 years ago

What is the final product of the following sequence of reactions? A. A B. B C. C D. D 21. Which of the following reacts the fast

Gala2k [10]

Answer:

Correct answer is Option A:

A. ethylene oxide (oxirane)

Explanation:

It reacts faster because it leads to a tertiary cation.

5 0

4 years ago

1.Peptide bond formation is accomplished as the amine nitrogen of the an-tRNA in the ____ carries out a _____ of the amino acid

Levart [38]

Answer:

Explanation:

A site, nucleophilic attack on the carbonyl carbon, tRNA of the P site

5 0

3 years ago

Having done the experiment, explain briefly how the mass of zinc not equal the mass of lead gained (hint: the periodic table)

masya89 [10]

Answer:

Due to the difference in the relative atomic masses and therefore, the molecular masses of Zn and Pb, one mole of Zn is about 3.2 times lighter than one mole of Pb

Explanation:

From the periodic table, we have;

The atomic number of zinc, Zn = 30

The atomic mass of zinc, Zn = 65.38 amu

The molar mass of zinc, Zn = 65.38 g/mol

The atomic number of lead, Pb = 82

The atomic mass of lead, Pb = 207.2 amu

The molar mass of lead, Pb = 207.2 g/mol

Therefore, whereby equal number of moles of Zn is lost and Pb is gained, we have;

Mass of 1 mole of Zn = 65.38 grams

Therefore, 1 gram of Zn = 1/65.38 moles = 0.0153 moles

0.12 grams of Zn = 0.12×0.0153 = 0.00184 moles of Zn

Given that equal number of moles of Zn and Pb are involved in the reaction, the number of moles of Pb gained = 0.00184 moles

The mass of Pb gained = Number of moles of Pb gained × Molar mass of Pb

The mass of Pb gained = 0.00184 × 207.2 = 0.38 g ≈ 0.4 g.

Amount of Pb gained = 0.43 g ≈ 0.4 g

4 0

3 years ago