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goldfiish [28.3K]
4 years ago
8

Given that an electromagnetic wave is generated by an oscillating electron, how are the frequency of the wave and the oscillatio

n frequency of
the electron related?

A. The frequency of the electromagnetic wave is inversely proportional to the oscillation frequency of the electron

B. The frequency of the electromagnetic wave is equal to the oscillation frequency of the electron

C. The frequency of the electromagnetic wave has no effect on the oscillation frequency of the electron

D. The frequency of the electromagnetic wave is directly proportional to the oscillation frequency of the electron

E. The frequency of the electromagnetic wave is half of the oscillation frequency of the electron
Chemistry
1 answer:
4vir4ik [10]4 years ago
4 0

Answer:

D

Explanation:

The frequency of the electromagnetic wave is directly proportional to the oscillation frequency of the electron.

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If I initially have a gas at a pressure of 12 kPa, a volume of 23 liters, and a temperature of 200 K, and then I raise the press
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Which type of change must occur to form a compound? (1) chemical (3) nuclear(2) physical (4) phase?
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Chemical forms compounds. 

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If you want to use a serial dilution to make a 1/50 dilution. The first dilution you make is a 1/5 dilution with a total volume
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0.2 mL stock solution, 0.8 solvent, 0.1 mL first solution and 0.9 solvent

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7 0
3 years ago
Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
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If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

  • V = 2.4 L = 0.0024
  • P = 86126.25 Pa
  • T =  287 K
  • m = 0.622
  • R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

4 0
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