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sesenic [268]
2 years ago
7

How many of u usses. zoom and wanna j oin it​

Chemistry
1 answer:
gogolik [260]2 years ago
4 0

mee÷eeeeeeer tooooo ooooooooooooooo

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What shows an atom correctly?
castortr0y [4]

Answer:

B

Explanation:

Atom consists of proton and neutron in center (often referred as nucleus) and electrons circling those things.

5 0
3 years ago
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How many grams of Co, are produced when 3.60 g of Fe 0 reacts with excess CO?
Tanya [424]

Answer:

2.98 g CO2

Explanation:

1. Balance the chemical equation

1 Fe2O3 + 3CO ->  2Fe + 3CO2

2. Use periodic table to find mass from each CO2 and Fe2O3  

3. Calculate

3.60 g Fe2O3 x \frac{1 mol Fe2O3}{159.69 g Fe2O3}x\frac{3 mol CO2}{1 mol Fe2O3} x\frac{44.01 g CO2}{1 mol CO2} =  2.98 g CO2

8 0
3 years ago
Manufacturing traditional clayware ceramics typically involves driving off the water of hydration in the clay minerals. The rate
zimovet [89]

The relation between activation energy, rate constant and temperature is given by Arrhenius equation

Arrhenius equation is

ln (K2/ K1) = Ea / R (1/T1- 1/T2)

K2 =  1×10−3s−1  T2 =  525 ∘C = 798 K

K1 = 1×10−4s−1  T1 =  485 ∘c = 758 K

Ea = ?

R = gas constant = 8.314 J / mol K

ln (K2/ K1) = ln (10^-3 / 10^-4) = 2.303 = Ea /8 .314 (1/758 - 1 / 798)

2.303 = Ea / 8.314 (0.00132 - 0.00125)

Ea = 2.303 X 8.314 / (0.00132 - 0.00125)  = 273530.6 J / mole

Ea = activation energy = 273.531 kJ / mole

3 0
3 years ago
What is the trend for atomic radii across the periods and down the group?
jok3333 [9.3K]

Answer:

So, in general, atomic radius decreases across a period and increases down a group. Across a period, effective nuclear charge increases as electron shielding remains constant.

Explanation:

Moving from left to right across a period, the atomic radius decreases. The nucleus of the atom gains protons moving from left to right, increasing the positive charge of the nucleus and increasing the attractive force of the nucleus upon the electrons.

Have a happy day! <3Miss Hawaii

5 0
3 years ago
How many grams of Na2O are produced when 70.7 g of Na reacts?<br> 4Na(s)+O2(g)→2Na2O(s)
LUCKY_DIMON [66]

Answer:

95.3 grams.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Na: 22.990;
  • O: 15.999.

How many moles of Na are consumed?

M(\mathrm{Na}) = \rm 22.990\; g\cdot mol^{-1}.

\displaystyle n(\mathrm{Na}) = \frac{m(\mathrm{Na})}{M(\mathrm{Na})} = \rm \frac{70.7\; g}{22.990\;g\cdot mol^{-1}}=3.07525\;mol.

How many moles of \mathrm{Na_2 O} formula units will be produced?

Consider the ratio between the coefficient of \mathrm{Na_2 O} and that of \mathrm{Na} in the equation:

\displaystyle \frac{n(\mathrm{Na_2 O})}{n(\mathrm{Na})} = \frac{2}{4} = \frac{1}{2}.

As a result,

\displaystyle n(\mathrm{Na_2 O}) = n(\mathrm{Na}) \cdot \frac{n(\mathrm{Na_2 O})}{n(\mathrm{Na})} = \rm \frac{1}{2}\times 3.07525\;mol = 1.53763\; mol.

What will be the mass of that many \mathrm{Na_2 O}?

Formula mass of \mathrm{Na_2 O}:

M(\mathrm{Na_2 O}) = \rm 2\times 22.990 + 15.999 = 61.979\; g\cdot mol^{-1}.

m(\mathrm{Na_2 O}) = n(\mathrm{Na_2 O})\cdot M(\mathrm{Na_2 O}) = \rm 1.53763\; mol\times 61.979\; g\cdot mol^{-1} \approx 95.3\; g.

7 0
3 years ago
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