We have that the Concentration of solution B is 2.5 times more than solution A's concentration.
<h3>UV(Ultra violent) rays</h3>
Question Parameters:
Upon UV-analysis, Solution B gave an absorbance of 1.0
Solution A gave an absorbance of 0. 4
Generally the equation for the Absorbance is mathematically given as
A = e*c*L
Therefore
For A solution
![0.4 = e*[cA]*L](https://tex.z-dn.net/?f=0.4%20%3D%20e%2A%5BcA%5D%2AL)
For B solution
![1.0 = e*[cB]*L](https://tex.z-dn.net/?f=1.0%20%3D%20e%2A%5BcB%5D%2AL)
Hence
![\frac{0.4}{ 1} = \frac{[cA]}{ cB}](https://tex.z-dn.net/?f=%5Cfrac%7B0.4%7D%7B%201%7D%20%3D%20%5Cfrac%7B%5BcA%5D%7D%7B%20cB%7D)
[cB] = 2.5 [cA]
Therefore
Concentration of solution B is 2.5 times more than solution A's concentration.
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Answer:
D
Explanation:
The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.
Answer:
Reducing the amount of water you use, by having a 5-minute shower or not running the water when washing up the dishes, can help protect vital wetlands. Plant scientists are also working to help conserve by developing crop varieties that use less water.
Explanation:
Answer:
Excess Reagent = oxygen
Explanation:
Limiting reagent: The substance that is totally consumed when the reaction is completed.
Excess reagent: The substance left after the limiting reagent is consumed completely
The balanced chemical equation for formation of water is as follow:
This means when 2 moles of hydrogen reacts with 1 mole of oxygen, 2 moles of water is produced.
Hence the ratio in which hydrogen and oxygen gas reacts is 2:1
Now if 2 mole hydrogen require 1 mole of oxygen ,then 4 mole hydrogen need 2 mole of oxygen.
or
Here 5 mole of oxygen is reacting but only 2 mole is required .
Oxygen is in excess.
To solve this we assume
that the gas inside is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:
T1 / V1 = T2 / V2
T2 = T1 x V2 / V1
T2 = 280 x 20.0 / 10
<span>T2 = 560 K</span>
