What is the oxidation number of phosphorus (P) in phosphoric acid (H3PO4)?
1 answer:
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61.24 is the molar mass of a gas which has a density of 0.00249 g/mL at 20.0 degrees celcius and 744.0 mm Hg.
Explanation:
given that:
density = 0.00249 g/ml () or 2.49 grams/litre
P = 744 mm Hg OR 0.978 atm
T = 20 Degrees or 293.15 Kelvin
R = 0.08206 Litre atm/mole K
molar mass =?
Formula used/
PV = nRT equation 1
here n is number of moles:
n =
putting the value of n and value of density in the equation 1:
PV = x RT
molar mass = x
= density x
=
= 61.24 is the molar mass of the gas.