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sergejj [24]
3 years ago
6

BEST GETS BRAINLIEST!!

Chemistry
1 answer:
tatuchka [14]3 years ago
3 0
Gee.  I'll have to guess at what's "commonly thought".

One thing is the scale.  Nobody has an accurate picture of the scale in
his head, because we never see a true-scale drawing.  THAT's because
it's almost impossible to draw one on paper.

Example:
Shrink the solar system and everything in it so that the Sun
is the size of a quarter (the 25¢ coin).
Then:
-- The Earth is in orbit around the sun, 8.6 feet from it. 
That's close enough that you might think you could find the
shrunken Earth.  Unfortunately, it's only 0.009 inch in diameter.

-- The shrunken Jupiter is a 'huge' gas giant almost 0.1 inch in diameter.
It's orbiting the sun, about 45 feet away from it.

-- The shrunken Uranus is another gas giant, about 0.035 inch in diameter.
It's orbiting the sun, about 165 feet away from it.

-- The nearest star outside of the solar system is 441 MILES away !
On the same shrunken scale !
And there's NOTHING between here and there !  

I think that's the biggest point to make about the REAL solar system ...
its utter emptiness.  With the sun reduced to something you can hold
in your hand, the planets are the size of grains of sand, with hundreds
of feet of nothingness between them.

Same for its mass:  The solar system is approximately nothing but a star.
That's it.  A star, with some dust and some gas around it, and here and there
in the neighborhood a microscopic pebble or a chip of mineral.  But mostly
it's nothing but a star ... if you went around and gathered up all that other
rubbish in the same bag and called it a part of the same solar system, the
sun would still have more than 99% of the total mass, and the bag would
hold less than 1% of it.

Book ... It's getting late, Hillary's fading, and that's all I can think of.
I hope this much is some help.
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trust me thats the right answer i am not goo at explanations

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As you move from left to right across a period, what happens to the atomic radii?
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Answer:

They decrease, because of the stronger effective nuclear charge.

Explanation:

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<em>Thus, the right choice is: They decrease, because of the stronger effective nuclear charge.</em>

<em></em>

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3 years ago
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If u (x) = negative 2 x squared and v (x) = StartFraction 1 Over x EndFraction, what is the range of (u circle ma poottay
KonstantinChe [14]
The range is negative numbers.
The interval for the range is .
***You might want to look at your functions again because I don't see a choice that matches.
Step-by-step explanation:
Given functions:


We are asked to find the range of .
I'm also going to look at the domain just to see if this possibly might change my range .
is the inner function. So we will consider the domain of that function first.
You only have to worry about division by zero for the function .
Since we are dividing by , we don't want to be zero.
So far the domain is all real numbers except .
Now let's move out.
exists for all numbers, . So we didn't want to include from before.
Now let's put it together:







So the domain is still all real numbers except at since we cannot divide by 0 and is 0 when .
with .
is positive for all numbers except .
So is negative for all numbers since negative divided by positive is negative.
So the range is only negative numbers.
Let's also look at the inverse:

Multiply both sides by :

Divide both sides by :

Take the square root of both sides:
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So can't be 0 and it also can't be positive because the inside of the square root will be negative (since negative divided by positive results in negative).
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