Answer:
3, fifths should be added.
2/10 = 1/5
4/10 = 2/5
6/10 = 3/5
Divide the tenth fractions by two, to get the anwser on the right.
Answer:
y= 3x -4
Step-by-step explanation:
The equation of a line can be written in the form of y=mx +c, where m is the slope and c is the y-intercept. This is also known as the slope-intercept form.

Since the given equation is in the slope-intercept form, we can identify its slope from the coefficient of x.
Slope= -⅓
The product of the slopes of perpendicular lines is -1.
Slope of perpendicular line


= 3
Thus, the equation of the perpendicular line is given by:
y= 3x +c
Substitute a pair of coordinates that the line passes through to find the value of c.
When x= 3, y= 5,
5= 3(3) +c
5= 9 +c
<em>Minus 9 on both sides:</em>
c= 5 -9
c= -4
Hence, the equation of the perpendicular line is y= 3x -4.
Additional:
For more questions on equation of perpendicular lines, do check out the following!
1. Decompose all numbers into prime factors
300 2 150 2 75 3 25 5 5 5 1 400 2 200 2 100 2 50 2 25 5 5 5 1 500 2 250 2 125 5 25 5 5 5 1
2. Write all numbers as the product of its prime factors
Prime factors of 300 = 22 . 3 . 52
Prime factors of 400 = 24 . 52
Prime factors of 500 = 22 . 53
3. Choose the common and uncommon prime factors with the greatest exponent
Common prime factors: 2 , 5
Common prime factors with the greatest exponent: 24, 53
Uncommon prime factors: 3
Uncommon prime factors with the greatest exponent: 31
4. Calculate the Least Common Multiple or LCM
Remember, to find the LCM of several numbers you must multiply the common and uncommon prime factors with the greatest exponent of those numbers.
LCM = 24. 53. 31 = 6000
Answer:
See below.
Step-by-step explanation:
The hypotenuse is 35.
-hope it helps
1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.
There are in total

many ways of doing so.
where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r
2.
C(x, 2) is the total number of pairs out of x objects, that we can form.
so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.
The total number of games is:
n(x)=2*C(x, 2) =

Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.
Answer: