What does this “e” mean in science atoms molecules etc etc

Which equation using element symbols correctly describes the reaction: "One molecule of methane plus two molecules of diatomic o

MrMuchimi

Answer:

CH4+2O2→2H2O+CO2

8 0

3 years ago

Read 2 more answers

Calculate the maximum solubility of silver carbonate, Ag2CO3 in g/L when in the presence of 0.057 M AgNO3. The solubility produc

Andreyy89

Answer:

Approximately $4.2 \times 10^{-7}\; \rm g \cdot L^{-1}$ .

Explanation:

Start by finding the concentration of $\rm Ag_2CO_3$ at equilibrium. The solubility equilibrium for

$\rm Ag_2CO_3 \; (s) \rightleftharpoons 2\, Ag^{+}\; (aq) + {CO_3}^{2-}\; (aq)$ .

The ratio between the coefficient of $\rm Ag_2CO_3$ and that of $\rm Ag^{+}$ is $1:2$ . For

Let the increase in $\rm {CO_3}^{2-}$ concentration be $+x\; \rm mol \cdot L^{-1}$ . The increase in $\rm Ag^{+}$ concentration would be $+2\,x\; \rm mol \cdot L^{-1}$ . Note, that because of the $0.057\; \rm mol \cdot L^{-1}$ of $\rm AgNO_3$ , the concentration of

The concentration of $\rm Ag^{+}$ would be $(0.057 + 2\, x) \; \rm mol\cdot L^{-1}$ .
The concentration of $\rm {CO_3}^{2-}$ would be $x\; \rm mol \cdot L^{-1}$ .

Apply the solubility product expression (again, note that in the equilibrium, the coefficient of $\rm Ag^{+}$ is two) to obtain:

$\begin{aligned}&\rm \left[Ag^{+}\right]^2 \cdot \left[{CO_3}^{2-}\right] = K_{\text{sp}} \\ & \implies (0.057 + x)^2\cdot x = 8.1 \times 10^{-12} \end{aligned}$ .

Note, that the solubility product of $\rm Ag_2CO_3$ , $K_{\text{sp}} = 8.1 \times 10^{-12}$ is considerably small. Therefore, at equilibrium, the concentration of

Apply this approximation to simplify $(0.057 + x)^2\cdot x = 8.1 \times 10^{-12}$ :

$0.057^2\, x \approx (0.057 + x)^2 \cdot x = 8.1 \times 10^{-12}$ .

$\begin{aligned} x &\approx \frac{8.1 \times 10^{-12}}{0.057^2}\end{aligned}$ .

Calculate solubility (in grams per liter solution) from the concentration. The concentration of $\rm Ag_2CO_3$ is approximately $\displaystyle \frac{8.1 \times 10^{-12}}{0.057^2}\; \rm mol\cdot L^{-1}$ , meaning that there are approximately $\displaystyle n = \frac{8.1 \times 10^{-12}}{0.057^2}\; \rm mol$ of

$\begin{aligned}m &= n \cdot M \\ &\approx \displaystyle \frac{8.1 \times 10^{-12}}{0.057^2} \; \rm mol\times 167.91\; g \cdot mol^{-1} \\ &\approx 4.2 \times 10^{-7}\; \rm g \end{aligned}$ .

As a result, the maximum solubility of $\rm Ag_2CO_3$ in this solution would be approximately $4.2 \times 10^{-7}\; \rm g \cdot L^{-1}$ .

8 0

3 years ago

5. How many formula units are in 1.62 moles of magnesium iodide?

PIT_PIT [208]

Answer: 9.75 x10^23

Explanation: you do 6.02x10^23 times 1.62. And then round to three digits.

6 0

3 years ago

Liquid bromine is added to sodium iodide crystals

gulaghasi [49]

The following chemical reaction will occur:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.

The chemical reaction is:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

(l) - liquid

(s) - solid

Learn more about:

balancing chemical equations

brainly.com/question/13971935

#learnwithBrainly

6 0

3 years ago

Find the volume of 200g of benzene, if the density of benzene is 0.88 g/mL.

Lina20 [59]

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question we have

$volume = \frac{200}{0.88} \\ = 227.2727...$

We have the final answer as

Hope this helps you

7 0

3 years ago