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algol13
4 years ago
5

A process or reaction which takes in heat from the surroundings is said to be

Chemistry
1 answer:
Salsk061 [2.6K]4 years ago
3 0
<span>A process or reaction which takes in heat from the surroundings is said to be </span><u>Endothermic.</u>
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As the energy of the molecules increases, the motion of the molecules _______.
Alexus [3.1K]

Answer:

the motion of molecules increases

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3 years ago
The length of a diagonal of a cube with edge length 3 in.
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Diagonal

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6. Which part leads the blood to the heart?
Dmitriy789 [7]

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An aqueous solution of sucrose (C12H22O11C12H22O11) is prepared by dissolving 7.6330 gg in sufficient deionized water to form a
Mariana [72]

Answer:

The answer to your question is 0.64 M

Explanation:

Data

Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g

volume = 25 ml

Molarity = ?

Process

1.- Calculate the molar weight of Sucrose

C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)

                = 144 + 22 + 176

                = 342 g

2.- Calculate the moles of sucrose

                   342 g ------------------ 1 mol

                    7.633 g ---------------  x

                     x = (7.633 x 1) / 342

                    x = 0.0223 moles

3.- Calculate the molarity

Molarity = moles / volume (L)

Molarity = 0.0223 / 0.035

Molarity = 0.64

6 0
3 years ago
What quantity of energy, in joules, is required to raise the temperature of 425 g of tin from room temperature, 25.0 °C, to its
Rama09 [41]

Answer:

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is 45.249 kiloJoules.

Explanation:

Mass of the tin ,m= 425 g

Heat capacity of the tin ,c= 0.227 J/g K

Initial temperature of the tin ,T_1= 25.0 °C = 298.15 K

Final temperature of the tin, T_2= 231.9 °C = 505.05 K

Let the heat required to change the temperature of tin from 298.15 K to 505.05 K be Q.

Q=mc\times (T_2-T_1)

=425 g\times 0.227 J/g K\times (505.05K - 298.15 K)=19,960.68 J=19.961 kJ

Heat required to melt tin at 505.05 K be Q'

The heat of fusion of tin metal =\Delta H_{fus}=59.2 J/g

Q'= m\times \Delta H_{fus}=425 g\times 59.2 J/g=25,287.5 J=25.288 kJ

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is:

= Q+Q' =  19.961 kJ + 25.288 kJ = 45.249 kJ

6 0
3 years ago
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