Answer:
The answer is 3-Phenylpropanoic acid (see attached structure)
Explanation:
From spectral data:
3005 cm-1 ⇒ carboxylic acid (broad band)
1670 cm-1 ⇒ C=C
1603 cm-1 ⇒ Aromatic C-C bond
H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).
Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.
Answer:
absorbed
Explanation:
because black absorbs the light around it
this is due to the difference in electron density. Butylamine has more electron density than ammonia. Due to this reason is a Butylamine stronger base than ammonia. BUtylamine has positive induction effect of -CH3 group electron density on N atom which increases
C. The number of neutrons
Since Carbon 12 has 6 neutrons
And carbon 13 has 7 neutrons.
You know that elements have equal protons (atomic number) and electrons
Answer:
Option b. 9.59
Explanation:
First, let us calculate the pH. This is illustrated below:
[H3O+] = 3.9 x 10-5 M
pH = —Log [H3O+]
pH = —Log [3.9 x 10-5]
pH = 4.41
Recall: pH + pOH = 14
4.41 + pOH = 14
Collect like terms
pOH = 14 — 4.41
pOH = 9.59
