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Shkiper50 [21]
3 years ago
14

When a plant responds to changes in the length of day by flowering during certain seasons, it is called

Chemistry
2 answers:
lina2011 [118]3 years ago
8 0

Answer: photoperiodism

Zanzabum3 years ago
7 0

Answer:  photoperiodism

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What is the wavelength if the frequency is 29.2 hz?
ZanzabumX [31]

Answer : The wavelength is 1.027\times 10^7m

Solution : Given,

frequency = 29.2 Hz

Formula used :

\nu=\frac{c}{\lambda}\\\lambda=\frac{c}{\nu}

where,

\nu = frequency

\lambda = wavelength

c = speed of light = 3\times 10^8m/s

Now put all the given values in this formula, we get the wavelength.

\lambda=\frac{3\times 10^8m/s}{29.2Hz}=0.1027\times 10^8m=1.027\times 10^7m                 (1Hz=1s^{-1})

Therefore, the wavelength is 1.027\times 10^7m

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What is the only nonmetal in group 14?
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The only nonmetal in group 14 is carbon.

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3 years ago
What are the products of the reaction below?:<br> calcium chloride+ silver nitrate
WARRIOR [948]

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2 years ago
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In their notebook you see that it takes 9 hours for a sixth of a 0.5M solution of BC2 to react. Unfortunately, you have somewher
trasher [3.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of BC_2 that should used originally is C_Z_o = 0.4492M

Explanation:

     From the question we are told that

         The necessary elementary step is  

                  2BC_2 ----->4C + B_2

          The  time taken for sixth of 0.5 M of reactant to react t = 9 hr

           The time available is t_a = 3.5 hr

             The desired concentration to  remain C  = 0.42M

Let Z be the reactant ,   Y be the first product and X the second product

Generally the elementary rate  law is mathematically as

                    -r_Z = kC_Z^2 = - \frac{d C_Z}{dt}

Where k is the rate constant ,  C_Z is the concentration of Z

From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )

 For second  order reaction

            \frac{1}{C_Z}  - \frac{1}{C_Z_o}  = kt

Where C_Z_o is the initial concentration of Z which a value of   C_Z_o = 0.5M

       From the question we are told that it take  9 hours  for the concentration of  the reactant to become

                 C_Z =  C_Z_o - \frac{1}{6}  C_Z_o

                  C_Z = 0.5  - \frac{0.5}{6}

                       = 0.4167 M

So      

                     \frac{1}{0.4167}  - \frac{1}{0.50}  =  9 k

                          0.400 = 9 k

                =>    k = 0.044\  L/ mol \cdot hr^{-1}

  For   C_Z = 0.42M

                \frac{1}{0.42} - \frac{1}{C_Z_o}  = 3.5 * 0.044

                2.38 -  0.154  =    \frac{1}{C_Z_o}

                           2.226  =    \frac{1}{C_Z_o}

                            C_Z_o = \frac{1}{2.226}

                             C_Z_o = 0.4492M

                       

           

             

         

4 0
3 years ago
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