The number of moles of b2o3 that will be formed is determined as 4 moles.
<h3>
Limiting reagent</h3>
The limiting reagent is the reactant that will be completely used up.
4 b + 3O₂ → 2b₂O₃
from the equation above;
4 b ------------> 2 b₂O₃
2b ------------> b₂O₃
2 : 1
3O₂ -------------> 2b₂O₃
3 : 2
b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;
4 b ------------> 2 moles of b2o3
8 moles -------> ?
= (8 x 2)/4
= 4 moles
Thus, the number of moles of b2o3 that will be formed is determined as 4 moles.
Learn more about limiting reactants here: brainly.com/question/14222359
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Covalent bond is the correct answer
The molar mass of PH3 is 34 g/mol, therefore the moles
is:
moles PH3 = 225 g / (34 g/mol)
moles PH3 = 6.62 mol
The balanced equation is:
4PH3(g) + 8O2(g) → P4O10(g) + 6H2O
We see that 4 mol of PH3 is required for every mol of
P4O10, therefore the number of moles of P4O10 is:
moles P4O10 = 6.62 mol * (1/4)
moles P4O10 = 1.65 mol
The molar mass of P4O10 is 283.89 g/mol, so the mass is:
mass P4O10 = 1.65 mol * 283.89 g/mol
mass P4O10 = 469.67 grams ~ 470 grams
Answer:
The percentage of ethylene glycol that is fatal is 0.15 %
Explanation:
If the toxic quantity of ethylene glycol in a 1kg or 1000 g body weight is 1.5 g then the percentage of ethylene glycol that is fatal is
ˣ 100 = 0.15%
Hence, the percentage of ethylene glycol that is toxic for any body weight is 0.15%. This percentage is very important in various aspects of science including drug discovery and food production/processing
