50 POINTS TIMED!! Which of the following shows the graph of y = 4x + 3? On a coordinate plane, an exponential function starts at
y = 3 in quadrant 2 and then increases rapidly into quadrant 1. On a coordinate plane, an exponential function starts at y = 0 in quadrant 2 and then increases rapidly in quadrant 2. On a coordinate plane, an exponential function starts at y = 0 in quadrant 2 and then increases rapidly into quadrant 1. On a coordinate plane, an exponential function starts at y = negative 3 in quadrant 3 and then increases rapidly into quadrant 1.
2 answers:
Answer:
1st Graph
Step-by-step explanation:
Parent Graph of Exponentials: f(x) = a(b)^x + d
Since we are only modifying the base exponent and <em>d</em> (vertical movement), we should see that if we are only moving up and down, that graph 1 is the best choice.
Alternatively, we could graph the equation and choose the best fit:
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Answer:
The Inequality to find the amount of money they spent on snack is
Maximum amount each person can spent on snack is 7.5.
Step-by-step explanation:
Given:
Total Money they had = 34
Cost of each ticket = 9.5
Number of persons = 2
Let the cost of snacks bought by each be x.
We need to write inequality and solve for the amount each persons spent on snacks.
Solution:
Now we can say that;
Number of persons multiplied by sum of Cost of each ticket and Cost of each person spent on snack should be less than or equal to Total money they had.
framing in equation form we get;
Hence the Inequality to find the amount of money they spent on snack is
On Solving the above Inequality we get;
Now By Using Subtracting property of Inequality we will subtract both side by 19 we get;
No By Division Property of Inequality we will divide both side by 2 we get;
Hence maximum amount each person can spent on snack is 7.5.
Interpreting the solution we get;
Now Cost of 1 ticket = $9.5
Number of person = 2
So total cost of ticket = $19
Total money they have = $34
Money left = Total money - total cost of ticket =$34 -$19 = $15
Amount of money left = $15
Now each buys the same snack.
So maximum amount of money each can spent on snack = $7.5