A helicopter is hovering 450 feet above the ground. The angle of elevation
1 answer:
Answer:
The distance of helicopter from the injured person is 542.82 feet
Step-by-step explanation:
Given as :
The height of the hovering helicopter above the ground = h = 450 feet
The angle of elevation from injured person to helicopter = Ф = 56°
Or, Let the distance of of helicopter from person = x feet
Now, From Triangle
∵ Sin Ф =
∴ Sin 56° =
Or, 0.8290 =
Or , x =
I.e x = 542.82 feet
So, The distance from injured person to helicopter = 542.82 feet
Hence The distance of helicopter from the injured person is 542.82 feet Answer
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Answer:
Step-by-step explanation:
Since; the density function diagrams were not included in the question; we will be unable to determine the best which depicts this problem.
However;
Let use X to represent the time required for the delivery.
Then X~N(3.8 ,0.8)
i.e
E(x) = 3.8
s.d(x) = 0.8
NOW; P(x>4) = P(X-3.8/0.8 > 4-3.8/0.8)
= P(Z > 0.25)
= 1-P(Z < 0.25)
=1 - Φ (0.25)
= 1 - 0.5987 ( from Normal table Φ (0.25) = 0.5987 )
= 0.4013
Thus; the probability a single delivery would take more than 4 hours is 0.4013
What is the z value corresponding to the interval boundary?
The z value is calculated as:
z = 0.25