A helicopter is hovering 450 feet above the ground. The angle of elevation

1 answer:

3 0

Answer:

The distance of helicopter from the injured person is 542.82 feet

Step-by-step explanation:

Given as :

The height of the hovering helicopter above the ground = h = 450 feet

The angle of elevation from injured person to helicopter = Ф = 56°

Or, Let the distance of of helicopter from person = x feet

Now, From Triangle

∵ Sin Ф = $\dfrac{\textrm Perendicular}{\textrm Hypotenuse}$

∴ Sin 56° = $\dfrac{\textrm h}{\textrm x}$

Or, 0.8290 = $\dfrac{\textrm 450}{\textrm x}$

Or , x = $\dfrac{\textrm 450}{\textrm 0.8290}$

I.e x = 542.82 feet

So, The distance from injured person to helicopter = 542.82 feet

Hence The distance of helicopter from the injured person is 542.82 feet Answer

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