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Law Incorporation [45]
3 years ago
8

Plzzz help me I’m bad with box and whisker plots

Mathematics
1 answer:
Komok [63]3 years ago
5 0
Hello!

Do you see the line right in the middle of the box? That is the median. It points down to about 15.5

Our answer is D) 15.5.

I hope this helps!
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Describe the effect of pollution on the environment​
Lorico [155]

Answer:

Hello!

~~~~~~~~~~~~~~~~~

Pollution needs to be dramatically reduced because it is destroying the environment we live in, contaminating our food and water, causing diseases and cancers in humans and wildlife, and destroying the air we breathe and the atmosphere that protects us from harmful ultra-violet radiation.

Step-by-step explanation: This the wrong subject but here is the answer.

Hope this helped you! Brainliest would be nice!

5 0
4 years ago
Read 2 more answers
Find the area of the shaded portion in the square. (assuming the central point of the arc is the corresponding corner)
-Dominant- [34]
To find the area of the shaded piece, subtract the square area to the area of the sector. 

<span>6 × 6 − <span>1/2</span><span>r^2 0</span></span>Subtract <span>☇ 
</span>36−1/2(6)2pi/2
☇
<span>36−<span>1/2</span>(6<span>)2</span><span><span>pi/</span>2
</span></span>☇
7.722 <span>✔

The area is 7.722. </span><span>✩</span>
6 0
3 years ago
Read 2 more answers
Your round-trip drive to work is 4 3/10 miles. how many miles do you drive to and from work in 3 days?
Yuki888 [10]
You take 4x3 = 12 and than add in the 3/10x3 which is 9/10 so you can write this as 12.9 or 12 and 9/10
7 0
4 years ago
Read 2 more answers
A loan of $1,020 was repaid at the end of 18 months with a check for $1,050. What annual rate of interest was charged?
marishachu [46]
We'll be assuming this is with simple interest.

now, a year has 12 months, thus in 18 months there are 18/12 years.

\bf ~~~~~~ \textit{Simple Interest Earned Amount}&#10;\\\\&#10;A=P(1+rt)\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$1050\\&#10;P=\textit{original amount deposited}\to& \$1020\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;t=years\to \frac{18}{12}\to &\frac{3}{2}&#10;\end{cases}

\bf 1050=1020\left[ 1+r\left( \frac{3}{2} \right) \right]\implies \cfrac{1050}{1020}=1+r\left( \frac{3}{2} \right) \implies \cfrac{35}{34}=1+r\left( \frac{3}{2} \right)&#10;\\\\\\&#10;\cfrac{35}{34}-1=\cfrac{3}{2}r\implies \cfrac{1}{34}=\cfrac{3}{2}r\implies \cfrac{2\cdot 1}{3\cdot 34}=r\implies \cfrac{1}{51}=r&#10;\\\\\\&#10;r\%=100\cdot \cfrac{1}{51}\implies r\approx\stackrel{\%}{1.96078431372549}
8 0
4 years ago
Evaluate g(x) = 0.023x3 + 0.4x2 − 2.1x + 8.3 for x = 2 and x = 4.
vivado [14]

Plug in 2 and 4 for every instance of x in the function g(x).

g(x) = 0.023x³ + 0.4x² − 2.1x + 8.3

g(2) = 0.023(2)³ + 0.4(2)² − 2.1(2) + 8.3 = 5.884

g(4) = 0.023(4)³ + 0.4(4)² − 2.1(4) + 8.3 = 7.772

answer: 5.884 and 7.772

6 0
3 years ago
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