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cestrela7 [59]
4 years ago
15

I have 24 ounces of salad 1/4 of the salad was lettuce 6 ounces rest is cucumber how many ounces of cucumber

Mathematics
1 answer:
Anettt [7]4 years ago
4 0
If a quarter of the salad is 6 ounces, then because you had 3/4th ounces of cucumber, you can do 6 multiplied by 3, which is 18.<span />
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Find the equation of the line that is perpendicular to y = –3x + 1 and passes though the point (6, 3).
noname [10]

Answer:

A. y=1/3x+1

Step-by-step explanation:

When finding a line that is perpendicular to another line, all you have to do is find the "opposite reciprocal" of the slope. In this case that means writing the slope as the fraction -3/1, and then flipping the fraction over (1/-3) and taking away the negative sign which gets you 1/3 for the slope of your new line. Now, all you have of your new equation is the slope. You need to take your new equation (y=1/3x+b) and plug in the x and y coordinates to that equation, and then solve for the last variable which is b. That solving process goes as follows:

3=1/3*6+b

3=2+b

1=b

now you can replace the b with 1 in your equation to get your final answer of y=1/3x+1

6 0
3 years ago
(Brainliest) PLEASE HELPP MEEE
zloy xaker [14]

Answer:

1. According to the angle bisector theorem, DAC = BAC

2. Same kind of goes for BC

3. X must be equal in both equations.   x= 3

9(3) -7 = 20

4(3) +8 = 20

Hope this helped!

8 0
3 years ago
5&lt;b-3. whats the answer????
9966 [12]

Answer:

5<b-3

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8<b

The variable will always go on the left side of the equation. To flip the equation, you must also flip the less than sign to a greater than sign.

b>8

Hope I helped!

8 0
3 years ago
Read 2 more answers
2/3 x 4/7 write the answer in the simplest form
trapecia [35]

Answer:

8/21

I don't think that it can be simplified further....

6 0
3 years ago
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Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.
meriva

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

5 0
3 years ago
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