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3 years ago

How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of 2.50x102 grams.

1 answer:

5 0

One way of expressing concentration is by percent. It may be on the basis of mass, mole or volume. Percent is expressed as the amount of solute per amount of the solution. For this case, we are given the percent by mass. In order to solve the amount of solute, we multiply the percent with the amount of the solution.

Mass of solute = percent by mass x mass solution
Mass of solute = 0.0350 x 2.50 x10^2 = 8.75 grams of solute

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3 years ago

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

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6.02 × 10²³ entities

From the question we have

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We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

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2 years ago

A chemist has some 40% acid solution, some 60% acid solution, and a wholebunch of free time. How many liters of each should be u

TiliK225 [7]

Answer:

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

Explanation:

Let volume of the 40% acid solution be x.

Let volume of the 60% acid solution be y.

Volume of solution formed after mixing both solution = 40 L

x + y = 40 L..[1]

Volume of acid 40% solution = 40% of x= 0.4x

Volume of acid 60% solution = 60% of y= 0.6y

Volume of acid formed = 45% of 40 L = $\frac{45}{100}\times 40=18L$

$0.4x+0.6y=18 L$ ..[2]

Solving [1] and [2]

x = 30 L , y = 10 L

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

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3 years ago