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Snezhnost [94]
3 years ago
11

Could you Show work please

Mathematics
2 answers:
notka56 [123]3 years ago
7 0

Answer:

2784 cm^2

Step-by-step explanation:

I have indicated in the pic there are 4 types of rectangles:

green : 20 x 4 = 80

red : 18 x 4 = 72

yellow : 20 x 18 = 360

blue : 18 x 16 = 288

green has 6 identical surface area so 6 x 80 = 480

red has 4 so 4 x 72 = 288

yellow has 4 so 4 x 360 = 1440

blue has 2 so 2 x 288 = 576

total : 480 + 288 + 1440 + 576 = 2784

stira [4]3 years ago
3 0
2784 cm 2

Hi run numbing
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Dahasolnce [82]

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7....10....16......28

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<em><u>therefore</u></em><em><u>:</u></em>

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<em><u>Hope</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>helped</u></em><em><u> </u></em><em><u>you</u></em><em><u>!</u></em>

6 0
3 years ago
(4x squared) to the 3rd power
Tom [10]

Answer:

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Step-by-step explanation:

.....................

7 0
3 years ago
Sean has some candy bars that he wants to give away. He is going to give each person 1/18 of a bar, and he has 2 3/4 to give awa
julsineya [31]

Answer:

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Step-by-step explanation:

Take the amount of candy and divide by the amount in a serving

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Change to an improper fraction

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11/4 ÷ 1/18

Copy dot flip

11/4 * 18/1

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8 0
3 years ago
HELP ILL GIVE A BRAINIEST
S_A_V [24]

Answer: The first one. 2 to the 20th power over 3 to the 8th power

Step-by-step explanation:

6 0
2 years ago
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

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y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

8 0
3 years ago
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