The answer is flighting advertising schedule. It is a publicizing progression or timing design in which promoting messages are booked to keep running amid interims of time that are isolated by periods in which no publicizing messages show up for the promoted thing.
The correct answer for the for loop is:
for (int i=1; i<200; i++){
if ((i%2)==0 && (i%3)==0){
cout << i << " ";
}
}
Python offers three options for running the loops. For iterating repeatedly through a sequence, use a for loop (that is either a list, a tuple, a dictionary, a set, or a string). This functions more like an iterator method seen in other object-oriented programming languages and is less like the for keyword found in other programming languages. The for loop allows us to run a series of instructions once for each element of a list, tuple, set, etc. There is no need to set an indexing variable before using the for loop.
Write a for loop that prints, in ascending order, all the positive integers less than 200 that are divisible by both 2 and 3, separated by spaces.
Learn more about loops here:
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Answer:
<u>Letter B is correct</u>. Diversification.
Explanation:
Diversification in this case is the best option for an investor with this profile. This is because in the passive approach it is considered the price fluctuation information of a stock and the history of its current and future earnings. Therefore, diversification is ideal for this type of investor, because diversifying investments reduces the risk of losses.
The answer would be that the company can keep costs too a minimum.
