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liraira [26]
3 years ago
11

An equilateral triangle with a side length of 6mm and a height of 5.2mm is divided vertically into halves. Find the area of one

of the halves PLZ INCLUDE SOLUTION :D
Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0

There are two ways you could go about solving this.

You could divide the length of the base (6mm) by 2 and use that to find the area or you could find the area of the whole triangle using 6mm and divide that by 2.

I will use the first method I described:

base = 6/2

base = 3 mm

height = 5.2 mm

area = bh/2

area = (3 * 5.2)/2

area = 7.8 square mm

(don't forget your units)


Using the other method would look like this:

area = bh/2

b = 6

h = 5.2

area = (6 * 5.2)/2

area = 15.6 square mm

area/2 = 7.8 square mm


As you can see either method yields the same result.

Hope this helped.

Cheers and good luck,

Brian

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On the number line above, points J, K, L, and M are integers, and JK:KL:KM = 2:1:3. What is the value of KM? number line shown b
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<h2>F. 12</h2>

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