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aksik [14]
3 years ago
15

Please post detailed answers to the following questions. Please use complete sentences. What are some of the challenges that you

might face if you wanted to observe and study stars from Earth? NEED TWO PARAGHRAPHS
Physics
1 answer:
Degger [83]3 years ago
8 0
As what Douglas Adams says, "<span>Space is big. Really big. You just won't believe how vastly, hugely, mind-bogglingly big it is. I mean, you may think it's a long way down the road to the chemist, but that's just peanuts to space."

The fact that the stars are very far from Earth, one can't fully understand the stars as it would require hundred of years to closely travel from earth to the stars because it is located million miles away from the Earth. Aside from its location, the stars are also hard to closely study because it emits lights that are harm for people when exposed longer. </span>
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Why must you balance an equation to describe correctly what happens in a chemical reaction
wariber [46]

Where you get all the steps when you finally get a reaction . Ex, vinegar and baking soda you go step by step.

Hope this helps :)

5 0
3 years ago
A 15.0 mW laser puts out a narrow beam 2.00 mm indiameter.
Murljashka [212]

Answer:

1341.03 V/m

Explanation:

The power output per unit area is the intensity and also the is the magnitude of the Poynting vector.

                                 S = \frac{P}{A} = cε₀E^{2} _{rms}

                             ⇒ \frac{P}{A} = cε₀E^{2}_{rms}

Where;

P is the power output

A is the area of the beam

c is speed of light

ε₀ is permittivity of free space 8.85 × 10⁻¹² F/m

E_{rms} is the average (rms) value of electric field

Making electricfield E_{rms} the subject of the equation

                                 E^{2}_{rms} = P / Acε₀

                                 E_{rms} = √(P / Acε₀)

But area A = πr²

                                 E_{rms} = √(P / πr²cε₀)                    

Given:

Output power, P = 15 mW = 0. 015 W

Diameter, d = 2 mm = 0.002 m

⇒ Radius, r = \frac{d}{2} = \frac{0.002}{2} = 0.001 m

Solving for average (rms) value of electric field;     

E_{rms} = \sqrt{\frac{0.015 W}{\pi * (0.001 m)^2 * (3 * 10^8 m/s) * (8.85 * 10^-12) C^2/Nm^2} }

                                E_{rms} = 1341.03 V/m

                             

                         

                                 

                                 

                                 

6 0
3 years ago
What is the main source of groundwater? A. precipitation falling into man-made wells B. precipitation seeping through pores and
Yuliya22 [10]

Answer:

B: precipitation seeping through pores and cracks in the ground

Explanation:

Man made wells aren't the main source because their isn't enough of them and morning dew doesn't go in to the ground in one main source.

5 0
3 years ago
in as small room fan of rating 50 watt is used for 10hrs 2bulb of rating 10v are used for 8hrs daily.calculate monthly. electric
Pie

Answer:

The electric bill for June is Rs198000

Explanation:

Convert volt to watt, but in order to do so I need to know the amps and since it is not provided I converted if the amps was 1.

I multiple 50 with 10 then  with 30 so I know how much watt the fan takes at June.

Since there are 2 light bulb I multiple 10 with 2 than with 8 than with 30.

15000 watts for the fan,

4800 watts for light bulb,

add them and then times it by 10.

Rs198000

4 0
3 years ago
Because plate movements have raised ancient sea floors above sea level,
Elena-2011 [213]
Because plate movements have raised ancient sea floors above sea level, _________?

<span>Answer : Limestone that began as coral reefs can be found on the continents.</span>

3 0
3 years ago
Read 2 more answers
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