3 years ago

A spring attached to a mass is at rest in the initial

Physics

2 answers:

svet-max [94.6K]3 years ago

6 0

Answer:

E=(1/2)kx^2

Explanation:

SOVA2 [1]3 years ago

5 0

Answer:

It's C on edge

Explanation:

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What weighs exactly 500 grams in the house?

Serga [27]

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3 years ago

the maximum displacement of an oscillatory motion is A=0.49m. determine the position x at which the kinetic energy of the partic

kipiarov [429]

Answer:0.4 m

Explanation:

Given

Maximum displacement A=0.49

The sum of kinetic and elastic potential energy is $\frac{1}{2}kA^2$

where k=spring constant

U+K.E.= $\frac{1}{2}kA^2$

when K.E.=U/2

K.E.=kinetic energy

U=Elastic potential Energy

$\rightarrow \ U+\frac{U}{2}=\frac{1}{2}KA^2\\\rightarrow \ \frac{3U}{2}=\frac{1}{2}KA^2\\\rightarrow \ U=\frac{1}{3}KA^2\\\rightarrow \ \frac{Kx^2}{2}=\frac{1}{3}KA^2\\\\x=\sqrt{\frac{2}{3}}A\\x=0.4\ m$