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mixer [17]
4 years ago
13

A spring attached to a mass is at rest in the initial

Physics
2 answers:
svet-max [94.6K]4 years ago
6 0

Answer:

E=(1/2)kx^2

Explanation:

SOVA2 [1]4 years ago
5 0

Answer:

It's C on edge

Explanation:

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I need the answer for all of these l don't understand any of this
ElenaW [278]
This should help, 
Search up the Scientific method and lookup for the meaning of each word.
I can't help with all of it but this should help for most 

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4 years ago
What is work in science
mr_godi [17]

Answer:

The scientific defenision of work reveals its relationship to energy; whenever work is done, energy is transfered.

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3 years ago
Frank is leaving Gainesville at 7:30 am and needs to be in Tampa by noon. He is cycling at an average speed of 18.3 mph. At what
garri49 [273]

If Frank leaves Gainesville at 7:30 am, the time he should arrive in Tampa is 12.00 pm after spending 4 hours 30 minutes on the road.

<h3>What is average speed? </h3>

The average speed of an object is the ratio of total distance to total time of motion.

V = total distance/total time

For Frank to be in Tampa by noon, he must spend atleast 4 hours 30 minutes on the road.

18.3 mph = d/4.5 h

d = 82.35 miles

The distance between Gainesville  and Tampa is 82.35 miles.

Thus, we can conclude that, if Frank leaves Gainesville at 7:30 am, the time he should arrive in Tampa is 12.00 pm after spending 4 hours 30 minutes on the road.

Learn more about average speed here: brainly.com/question/6504879

#SPJ1

4 0
2 years ago
Sasha is interviewing people for a study he is doing. Before he starts the interview, Sasha explains the purpose of the study an
Alex73 [517]
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Sasha is informing participants about the study and making sure they wish to participate.
5 0
3 years ago
How much heat must be removed from 456 g of water at 25.0°C to change it into ice at - 10.0°C ? The specific heat of ice is 2090
cupoosta [38]

Answer:209.98 kJ

Explanation:

mass of water m=456 gm

Initial Temperature of Water T_i=25^{\circ}C

Final Temperature of water T_f=-10^{\circ}C

specific heat of ice c=2090 J/kg-K

Latent heat L=33.5\times 10^4 J/kg

specific heat of water c_{water}=4.184 KJ/kg-K

Heat require to convert water at T=25^{\circ}C to T=0^{\circ}C

Q_1=0.456\times 4.184\times (25-0)=47.69 kJ

Heat require to convert water at T=0^{\circ} to ice at T=0^{\circ}

Q_2=m\times L=0.456\times 33.5\times 10^4=152.76 kJ

heat require to convert ice at T=0^{\circ} C\ to\ T=-10^{\circ} C

Q_3=0.456\times 2090\times (0-(-10))=9.53 kJ

Total heat Q=Q_1+Q_2+Q_3

Q=47.69+152.76+9.53=209.98 kJ

7 0
3 years ago
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