7.5 pounds of the $0.82 per lb candy must be used in the mixture.
<h3>How many pounds of each candy should we use?</h3>
First, let's define the variables:
- x = pounds of the $0.82 candy used.
- y = pounds of the $1.36 candy used.
We want to make 9 lb of mixture, then:
x + y = 9.
And the price of these 9 pounds must be $0.91, then we can write:
x*$0.82 + y*$1.36 = 9*$0.91 = $8.19
Then we have a system of equations:
x + y = 9.
x*$0.82 + y*$1.36 = $8.19
We can isolate y on the first equation so we get:
y = 9 - x
Now we can replace that on the other equation:
x*$0.82 + (9 - x)*$1.36 = $8.19
And now we can solve this for x.
x*($0.82 - $1.36) = $8.19 - 9*$1.36
-x*$0.54 = -$4.05
x = (4.05/0.54) = 7.5
So 7.5 pounds of the $0.82 per lb candy must be used in the mixture.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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