Answer:
b
Explanation:
and if that wrong let me know cause jm my science class its b
Explanation:
Polarity is defined as the development of partial charges on the atoms of a molecule. In a water molecule, there are hydrogen and oxygen atoms.
Due to the difference in electronegativity of both hydrogen and oxygen atom there is development of partial positive charge on hydrogen atom and a partial negative charge on oxygen atom.
So, when bond between hydrogen and oxygen will break down then it will form hydrogen ions () and oxygen ions ().
Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule.
When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.
So, oxygen atom has an affinity towards cations and hydrogen atom has an affinity for anions.
Thus, we can conclude that following interactions and processes contribute to the dissolution of ionic compounds in water:
1. Affinity of oxygen towards cations
2. Ion–dipole interactions
4. Hydration
6. Affinity of hydrogen towards anions
<h3>
Answer:</h3>
259,000 Joules
<h3>
Explanation:</h3>
To calculate the heat energy needed to change 100 grams of liquid water at 75°C to vapor at 225°C, we will do this in steps;
<h3>
Step 1: Heat energy required to raise the temp of water from 75°C to 100°C</h3>
Mass of water = 100 g
Heat capacity of water = 4.184J/g °C
Temperature change (75°C to 100°C) = 25°C
Using the formula to get Quantity of heat;
Q = mcΔT
= 100 g × 4.184 J/g °C × 25°C
= 10,460 joules
<h3>
Step 2: Heat required to change water at 100°C to vapor at 100°C</h3>
Mass of water = 100 g
Heat of vaporization = 2,256 J/g
Heat required to change water to vapor without a change in temperature is given by;
Q = m × Lv
= 100 × 2,256 J/g
= 225,600 Joules
<h3>
Step 3: Heat energy required to raise the temperature of ice from 100°C to 225°C.</h3>
Mass of vapor = 100 g
Specific heat of gas = 1.84 J/g °C
Change in temperature (100°C to 225°C) = 125°C
Therefore;
Q = mcΔT
= 100 g × 1.84 J/g °C × 125°C
= 23,000 joules
<h3>Step 4: Total heat energy required</h3>
Total energy = 10,460 J + 225,600 J + 23,000 J
= 259,060 J
= 259,000 J(approx)
Therefore, heat energy required is 259,000 Joules
False. Eyeglasses do not cover all around the eye however safety goggles do