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stira [4]
3 years ago
5

8. How long does it take a 19 kW steam engine to do 6.8 x 107 J of work?

Chemistry
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

3.58 × 10³ seconds or 59.65 minutes

Explanation:

We are given;

  • Power of a steam engine as 19 kW
  • Work done as 6.8 × 10^7 Joules

We are required to calculate time;

We need to know that;

  • Power = Work done ÷ time
  • Power is the rate of doing work.

19 kW = 19,000 Watt

Rearranging the formula;

time = Work done ÷ power

       =  6.8 × 10^7 Joules ÷ 19,000 watt

       = 3578.95 seconds

        = 3.58 × 10³ seconds

But, 60 seconds = 1 minute

Therefore, t = 59.65 minutes

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Which statement is correct regarding the reaction below? 3A + 2B yields C + 2D The rate of formation of D is twice the rate of d
Vedmedyk [2.9K]

Answer:

The correct statements are:

The rate of disappearance of B is twice the rate of appearance of C.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

3A + 2B → C + 2D

Rate of the reaction:

R=-\frac{1}{3}\times \frac{d[A]}{dt}=-\frac{1}{2}\times \frac{d[B]}{dt}

-\frac{1}{3}\times \frac{d[A]}{dt}=\frac{1}{1}\times \frac{d[C]}{dt}

-\frac{1}{3}\times \frac{d[A]}{dt}=\frac{1}{2}\times \frac{d[D]}{dt}

The rate of disappearance of B is twice the rate of appearance of C.

\frac{1}{1}\times \frac{d[C]}{dt}=-\frac{1}{2}\times \frac{d[B]}{dt}

2\times \frac{1}{1}\times \frac{d[C]}{dt}=-\frac{1}{1}\times \frac{d[B]}{dt}

8 0
3 years ago
Read 2 more answers
A 232-lb fullback runs the 40-yd dash at a speed of 19.8 ± 0.1 mi/h.
Neporo4naja [7]

Answer:

(a)  7.11 x 10⁻³⁷ m

(b)  1.11 x 10⁻³⁵ m

Explanation:

(a)  The de Broglie wavelength is given by the expression:

λ = h/p = h/mv

where h is plancks constant, p is momentum which is equal to mass times velocity.

We have all the data required to calculate the wavelength, but first we will have to convert the velocity to m/s, and the mass to kilograms to work in metric system.

v = 19.8 mi/h x ( 1609.34 m/s ) x ( 1 h / 3600 s ) = 8.85 m/s

m = 232 lb x ( 0.454 kg/ lb ) = 105.33 kg

λ = h/ mv = 6.626 x 10⁻³⁴ J·s / ( 105.33 kg x 8.85 m/s ) = 7.11 x 10⁻³⁷ m

(b) For this part we have to use the uncertainty principle associated with wave-matter:

ΔpΔx > = h/4π

mΔvΔx > = h/4π

Δx = h/ (4π m Δv )

Again to utilize this equation we will have to convert the uncertainty in velocity to m/s for unit consistency.

Δv = 0.1 mi/h x ( 1609.34 m/mi ) x ( 1 h/ 3600 s )  

     = 0.045 m/s

Δx = h/ (4π m Δv ) = 6.626 x 10⁻³⁴ J·s / (4π x 105.33 kg x 0.045 m/s )

     = 1.11 x 10⁻³⁵ m

This calculation shows us why we should not be talking of wavelengths associatiated with everyday macroscopic objects for we are obtaining an uncertainty of 1.11 x 10⁻³⁵ m for the position of the fullback.

5 0
3 years ago
What is the most corrosive element in the periodic table?
Fittoniya [83]

Answer:

Fluorine is the most corrosive element in the periodic table.

Explanation:

4 0
3 years ago
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Which bond is broken when energy is released?
blsea [12.9K]
Energy is released when a new bonds form.
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Help plz:))) I’ll mark u brainliest
tatuchka [14]
The correct answer is

B.The elements all have three valence electrons
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3 years ago
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