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stira [4]
3 years ago
5

8. How long does it take a 19 kW steam engine to do 6.8 x 107 J of work?

Chemistry
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

3.58 × 10³ seconds or 59.65 minutes

Explanation:

We are given;

  • Power of a steam engine as 19 kW
  • Work done as 6.8 × 10^7 Joules

We are required to calculate time;

We need to know that;

  • Power = Work done ÷ time
  • Power is the rate of doing work.

19 kW = 19,000 Watt

Rearranging the formula;

time = Work done ÷ power

       =  6.8 × 10^7 Joules ÷ 19,000 watt

       = 3578.95 seconds

        = 3.58 × 10³ seconds

But, 60 seconds = 1 minute

Therefore, t = 59.65 minutes

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Lina20 [59]

Answer:

Single Displacement reaction  

In a displacement reaction, a more reactive element replaces a less reactive element from a compound.

Change in colour takes place with no precipitate forms.

Metals react with the salt solution of another metal.

Examples:

2KI + Cl2 → 2KCl + I2

CuSO4 + Zn → ZnSO4 + Cu

Double displacement reaction

In a double displacement reaction, two atoms or a group of atoms switch places to form new compounds.

Precipitate is formed.

Salt solutions of two different metals react with each other.

Examples:  

Na2SO4 + BaCl2 → BaSO4 + 2NaCl

2KBr + BaCl2 → 2KCl + BaBr2

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8 0
3 years ago
Products: 1-methylcyclohexene, 3-methylcyclohexene, methylenecyclohexane
Lostsunrise [7]

Answer:

See explanation

Explanation:

The reaction that we are considering here is quite a knotty reaction. It is difficult to decide if the mechanism is actually E1 or E2 since both are equally probable based on the mass of scientific evidence regarding this reaction. However, we can easily assume that the methylenecyclohexane was formed by an E1 mechanism.

Looking at the products, one could convincingly assert that the reaction leading to the formation of the two main products proceeds via an E1 mechanism with the formation of a carbocation intermediate as has been shown in mechanism attached to this answer. Possible rearrangement of the carbocation yields the 3-methylcyclohexene product.

8 0
3 years ago
A 15.0-L vessel contains 0.50 mol CH4 with a pressure of 1.0 atm. After 0.50 mol C2H6 is added to the vessel, what is the partia
Kazeer [188]

The partial pressure of methane in the mixture of methane and ethane has been 1 atm.

Partial pressure has been the pressure exerted by a gas in the solution or mixture. The partial pressure of each gas has been the total pressure of the gaseous mixture.

The partial pressure of the gas has been dependent on the volume, temperature, and concentration of the gas.

The given methane has a partial pressure of 1 atm in the 15 L vessel. The addition of ethane results in the change in the total pressure of the mixture, as there have been additional moles of solute that contributes to the solution pressure.

However, since there has been no change in the concentration and volume of methane, the pressure exerted by methane has been the same. Thus, the partial pressure of methane has been 1 atm.

For more information about the partial pressure, refer to the link:

brainly.com/question/14623719

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Answer:

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Explanation:

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