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3 years ago

8. How long does it take a 19 kW steam engine to do 6.8 x 107 J of work?

Chemistry

1 answer:

kykrilka [37]3 years ago

8 0

Answer:

3.58 × 10³ seconds or 59.65 minutes

Explanation:

We are given;

Power of a steam engine as 19 kW
Work done as 6.8 × 10^7 Joules

We are required to calculate time;

We need to know that;

Power = Work done ÷ time
Power is the rate of doing work.

19 kW = 19,000 Watt

Rearranging the formula;

time = Work done ÷ power

= 6.8 × 10^7 Joules ÷ 19,000 watt

= 3578.95 seconds

= 3.58 × 10³ seconds

But, 60 seconds = 1 minute

Therefore, t = 59.65 minutes

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Answer:

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Explanation:

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For the reaction between Pb(NO3)2 and NH4Cl , the net ionic equation is;

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Consider the equilibrium reaction. 2 A + B − ⇀ ↽ − 4 C After multiplying the reaction by a factor of 2, what is the new equilibr

vredina [299]

Answer : The correct expression for equilibrium constant will be:

$K_c=\frac{[C]^8}{[A]^4[B]^2}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$4A+2B\rightleftharpoons 8C$

The expression of $K_c$ will be,

$K_c=\frac{[C]^8}{[A]^4[B]^2}$

Therefore, the correct expression for equilibrium constant will be, $K_c=\frac{[C]^8}{[A]^4[B]^2}$

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2 years ago

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Answer:

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