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tatuchka [14]
3 years ago
11

A cylinder and a cone have congruent heights and radii.what is the ratio of the volume of the cone to the volume of the cylinder

?
Mathematics
2 answers:
kirill [66]3 years ago
7 0
Cone=(hpr^2)/3, cylinder=hpr^2, so the ratio:

cone:cylinder=1/3:1 or using integers by convention:

cone:cylinder=1:3
NemiM [27]3 years ago
4 0

Answer:

1: 3 ratio of the volume of the cone to the volume of the cylinder

Step-by-step explanation:

Volume of cone(V) is given by:

V = \frac{1}{3} \pi r^2h

where, r is the radius and h is the height of the cone.

Volume of cylinder(V') is given by:

V' = \pi r'^2h'

where,  r' is the radius and h' is the height of the cylinder.

As per the statement:

A cylinder and a cone have congruent heights and radii.

⇒r = r' and h = h'

then;

\frac{V}{V'} = \frac{ \frac{1}{3} \pi r^2h}{\pi r'^2h'} = \frac{ \frac{1}{3} \pi r'^2h'}{\pi r'^2h'}

⇒\frac{V}{V'} =\frac{1}{3} = 1 : 3

Therefore, the ratio of the volume of the cone to the volume of the cylinder is, 1 : 3

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Shkiper50 [21]

Answer:

infinite

Step-by-step explanation:

  • x=1
  • y=3

Let the linear equation in two variables be ax+by+c=0

Put values

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3 years ago
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OverLord2011 [107]

Answer:

11

Step-by-step explanation:

1st plug in the given numbers for each variable (the letters)

4 x 6 ÷ 3 + 3 =

Next, use the order of operations to solve the expression.

4 x 6 ÷ 3 + 3 =

24 ÷ 3 + 3 =

8 + 3 = 11

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3 years ago
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What is the degree of 12x4 - 8x + 4x2 - 3?<br><br> A. 8<br> B. 4<br> C. 3<br> D. 12
Soloha48 [4]
In this problem, we are asked to determine the degree of the given expression 12X4 - 8X + 4X2 -3. To answer this, first, we need to arrange the mathematical expression in descending order with respect to its power such as the new arrangement will become 12x4 + 4x2 -8x -3. The degree is clearly visible and it is 4. Therefore, the answer to this problem is the letter "B" which is 4.
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3 years ago
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Evaluate the expression for x=5, y=3,and z=1/4. <br> 5x−6y+20z/4yz
Anna11 [10]
Just substitute each number into the expression:
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3 years ago
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BD is the angle bisector of
AlexFokin [52]

Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

m\angle ABD=m\angle DBC

3x=x+20

3x-x=20

2x=20

Divide both sides by 2.

x=\dfrac{20}{2}

x=10

Now,

m\angle DBC=(x+20)^\circ

m\angle DBC=(10+20)^\circ

m\angle DBC=30^\circ

And,

m\angle ABC=(3x)^\circ+(x+20)^\circ

m\angle ABC=(4x+20)^\circ

m\angle ABC=(4(10)+20)^\circ

m\angle ABC=(40+20)^\circ

m\angle ABC=60^\circ

Therefore, m\angle DBC=30^\circ,m\angle ABD=30^\circ and m\angle ABC=60^\circ.

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