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tatuchka [14]
3 years ago
11

A cylinder and a cone have congruent heights and radii.what is the ratio of the volume of the cone to the volume of the cylinder

?
Mathematics
2 answers:
kirill [66]3 years ago
7 0
Cone=(hpr^2)/3, cylinder=hpr^2, so the ratio:

cone:cylinder=1/3:1 or using integers by convention:

cone:cylinder=1:3
NemiM [27]3 years ago
4 0

Answer:

1: 3 ratio of the volume of the cone to the volume of the cylinder

Step-by-step explanation:

Volume of cone(V) is given by:

V = \frac{1}{3} \pi r^2h

where, r is the radius and h is the height of the cone.

Volume of cylinder(V') is given by:

V' = \pi r'^2h'

where,  r' is the radius and h' is the height of the cylinder.

As per the statement:

A cylinder and a cone have congruent heights and radii.

⇒r = r' and h = h'

then;

\frac{V}{V'} = \frac{ \frac{1}{3} \pi r^2h}{\pi r'^2h'} = \frac{ \frac{1}{3} \pi r'^2h'}{\pi r'^2h'}

⇒\frac{V}{V'} =\frac{1}{3} = 1 : 3

Therefore, the ratio of the volume of the cone to the volume of the cylinder is, 1 : 3

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Answer:

(A)∠A = 82.2°,∠C = 62.8°, c = 17.1

Step-by-step explanation:

In Triangle ABC

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Using Law of SInes

\dfrac{a}{\sin A} =\dfrac{b}{\sin B} \\\dfrac{19}{\sin A} =\dfrac{11}{\sin 35^\circ} \\11*\sin A=19*\sin 35^\circ\\\sin A=(19*\sin 35^\circ) \div 11\\A= \arcsin [(19*\sin 35^\circ) \div 11]\\A=82.2^\circ

Now:

\angle A+\angle B+\angle C=180^\circ\\35^\circ+82.2^\circ+\angle C=180^\circ\\\angle C=180^\circ-[35^\circ+82.2^\circ]\\\angle C=62.8^\circ

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