what is the perimeter of polygon of (-4, 7), (6, 7), 6,- 2), (-8, -2), (-8, 3), (-4, 3) please help I don’t understand!

A square has sides with lengths of (x - 2) units. A rectangle has a length of x units and a width of

vagabundo [1.1K]

Answer:

(A)The area of the square is greater than the area of the rectangle.

(C)The value of x must be greater than 4

(E)The area of the rectangle is $(x^2-4x) \:Square \:Units$

Step-by-step explanation:

The Square has side lengths of (x - 2) units.

Area of the Square

$(x-2)^2=(x-2)(x-2)=x^2-2x-2x+4\\=(x^2-4x+4) \:Square \:Units$

The rectangle has a length of x units and a width of (x - 4) units.

Area of the Rectangle = $x(x-4)=(x^2-4x) \:Square \:Units$

<u>The following statements are true:</u>

(A)The area of the square is greater than the area of the rectangle.

This is because the area of the square is an addition of 4 to the area of the rectangle.

(C)The value of x must be greater than 4

If x is less than or equal to 4, the area of the rectangle will be negative or zero.

(E)The area of the rectangle is $(x^2-4x) \:Square \:Units$

3 0

3 years ago

From a deck of five cards numbered 2, 4, 6, 8, and 10, respectively, a card is drawn at random and replaced. this is done three

Serga [27]

Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, $2+2+8 = 12$ , and there are no other possibilities, unless you consider the various permutations of the terms.

So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.

Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.

So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of $5 \times 5 \times 5 = 5^3 = 125$ possible triplets.

Once we know the "good" cases and the total number of possible cases, the probability is simply computed as

$P = \cfrac{\text{number of favourable cases}}{\text{number of all possible cases}} = \cfrac{3}{125}$

3 0

3 years ago

Tommy can exchange 8 euros for 11 dollars.

Georgia [21]

Answer:

9 dollars and 40 cents

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Cans someone pls give me the answer to this?

romanna [79]

Answer:the value drops 100$ every 3 years

Step-by-step explanation:

moves down 100 every three years

8 0

2 years ago

Write a rule for the linear function in the table.

JulijaS [17]

Answer:

I guess that you want to know the transformations:

We start with:

f(x) = y = 4*x + 3

a)the transformed function is:

f(x) = y = -4*x - 3

So the sign changed.

This means that we go from (x, y) to (x, - y)

This is a reflection over the x-axis which changes the sin of the y component.

b) Now we go to f(x) = 4*x + 3

So the coefficient in the leading term changed.

This is a horizontal contraction:

A horizontal contraction of factor K for the function g(x) is: g(K*x)

In our case, we have:

f(K*x) = 4*(k*x) + 3 = x + 3

4*k*x = x

4*k = 1

k = 1/4

Then the transformation is an horizontal contraction of scale factor 1/4.

6 0

2 years ago