Find the product of x^2+2x-4 and 3x.

Mathematics

1 answer:

vladimir1956 [14]3 years ago

7 0

$3x({x}^{2} + 2x - 4)$

$3x \times {x}^{2} = {3x}^{3}$

$3x \times 2x = 6 {x}^{2}$

$3x \times - 4 = - 12x$

$b. \: 3 {x}^{3} + 6 {x}^{2} - 12x$

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PLZZZ HELP DUE IN 5 MINS

iris [78.8K]

Answer:

{(2, 9), (5, 9), (1, -6), (-5, 5), (2,9), (5,9), (1,−6), (−5,5)}

Step-by-step explanation:

recall that for a function to be valid, every input must give one and only 1 output. (i.e every x-ordinate must have only one unique corresponding y-ordinate)

I have highlighted in bold and underlined the entries for each of the other choices where an x-value gives more than one possible y-value, hence these are not functions. only the first option satisfies this condition:

{(2, 9), (5, 9), (1, -6), (-5, 5), (2,9), (5,9), (1,−6), (−5,5)} Every x-value has a unique y-value, so it is possible that this is a function.

{(6, 6), (6, 8), (-8, -7), (-3, -8), (6,6),(6,8),(−8,−7),(−3,−8)} (not a function)

{(1, 8), (9, -3), (7, -4), (7, -6), (1,8),(9,−3),(7,−4),(7,−6)} (not a function)

{(-5, -1), (-3, -7), (-5, 3), (-7, -4), (−5,−1),(−3,−7),(−5,3),(−7,−4)} (not a function)

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3 years ago

List the first six common multiples of 6 and 9

V125BC [204]

Answer:

The first few multiples of 6 and 9 are (6, 12, 18, 24, 30, . . . ) and (9, 18, 27, 36, . . . )

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2 years ago

The position s(t) of a robot moving along a track at time t is given by s(t)=9t^2−90t+4.

Xelga [282]

The total distance traveled by the robot from t=0 to t=9 is 1422 units

Integration is a way in which smaller components are brought together in pieces to form a whole. Integration can be used in finding areas, volumes and so on.

Given that the position s(t) at any time t is given by the function:

s(t)=9t²−90t+4

The total distance traveled by the robot from t=0 to t=9 can be gotten by integrating the position function within the limits 0< t < 9

Therefore:

$Total\ distance = \int\limits^9_0 {s(t) \, dt \\\\Total\ distance = \int\limits^9_0 {(9t^2-90t+4) \, dt\\\\Total\ distance = [3t^3-45t+4t]_0^9\\\\Total\ distance=-1422\ units$