Answer:
Part 1) "a" value is ![2](https://tex.z-dn.net/?f=2)
Part 2) The vertex is the point ![(1,8)](https://tex.z-dn.net/?f=%281%2C8%29)
Part 3) The equation of the axis of symmetry is ![x=1](https://tex.z-dn.net/?f=x%3D1)
Part 4) The vertex is a minimum
Part 5) The quadratic equation in standard form is ![y=2x^{2}-4x+10](https://tex.z-dn.net/?f=y%3D2x%5E%7B2%7D-4x%2B10)
Step-by-step explanation:
we know that
The equation of a vertical parabola into vertex form is equal to
![y=a(x-h)^{2}+k](https://tex.z-dn.net/?f=y%3Da%28x-h%29%5E%7B2%7D%2Bk)
where
(h,k) is the vertex of the parabola
if a > 0 then the parabola open upward (vertex is a minimum)
if a < 0 then the parabola open downward (vertex is a maximum)
The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex
so
![x=h](https://tex.z-dn.net/?f=x%3Dh)
In this problem we have
-----> this is the equation in vertex form of a vertical parabola
The value of ![a=2](https://tex.z-dn.net/?f=a%3D2)
so
a>0 then the parabola open upward (vertex is a minimum)
The vertex is the point ![(1,8)](https://tex.z-dn.net/?f=%281%2C8%29)
so
![(h,k)=(1,8)](https://tex.z-dn.net/?f=%28h%2Ck%29%3D%281%2C8%29)
The equation of the axis of symmetry is ![x=1](https://tex.z-dn.net/?f=x%3D1)
The equation of a vertical parabola in standard form is equal to
![y=ax^{2}+bx+c](https://tex.z-dn.net/?f=y%3Dax%5E%7B2%7D%2Bbx%2Bc)
Convert vertex form in standard form
![y=2(x-1)^{2}+8](https://tex.z-dn.net/?f=y%3D2%28x-1%29%5E%7B2%7D%2B8)
![y=2(x^{2}-2x+1)+8](https://tex.z-dn.net/?f=y%3D2%28x%5E%7B2%7D-2x%2B1%29%2B8)
![y=2x^{2}-4x+2+8](https://tex.z-dn.net/?f=y%3D2x%5E%7B2%7D-4x%2B2%2B8)
![y=2x^{2}-4x+10](https://tex.z-dn.net/?f=y%3D2x%5E%7B2%7D-4x%2B10)
see the attached figure to better understand the problem