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ipn [44]
3 years ago
6

4. The data shows the number of siblings each student in a 9th-grade class has.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

The correct option is Mean and standard deviation.

Step-by-step explanation:

The data set provided, arranged in ascending order is:

S = {0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 1 , 2 , 2 , 2 , 2 , 2 , 2 , 2 , 3 , 3 , 3 , 4 , 4}

Now, it is provided that Macy was absent when the data was collected and the class guessed she had 4 siblings. When  she returned, they found out she actually has 9 siblings.

So, the new data set is:

X = {0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 1 , 2 , 2 , 2 , 2 , 2 , 2 , 2 , 3 , 3 , 3 , 4 , 9}

The mean of a data set is the average value representing the entire data.

\bar X=\frac{1}{n}\sum X_{i}

The median is the middle value of the data set.

The inter-quartile range is the difference between the first and the third quartile.

The standard deviation is the value that represents how dispersed the data values are.

SD=\sqrt{\frac{1}{n}\sum (X_{i}-\bar X)^{2}}

From all the above statistic, the mean and standard deviation are the only ones that uses all the observations in the data set to compute their value.

So, on changing one of the 4s by a 9, the set of measures that will be affected are the mean and standard deviation.

Thus, the correct option is Mean and standard deviation.

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2 years ago
Is 2/3greater than 0.67
pickupchik [31]

Answer:

0.67>2/3

Step-by-step explanation:

If you divide 2 by 3, you will end up with 0.6.

Now, you can compare the two numbers 0.6 and 0.67.

3 0
2 years ago
How to write -2x + y = -3 in slope intercept form? Preferably with steps.
Montano1993 [528]

Answer:

y = 2x - 3

Step-by-step explanation:

Start by writing out the given equation.

-2x + y = -3

The goal is to isolate the variable y.

For this equation, all you need to do is add 2x to each side.

-2x + y + 2x = -3 + 2x

Therefore, the answer is y = 2x -3.

I don't know if you are are familiar with the equation y = mx + b, but here's a little refresher. m is the slope, or in this case 2. b is the y-intercept, or in this case -3.

The equation y = mx + b is slope intercept form, so if you know this, you should be able to write any equation in slope intercept form.

Hope this helps!

6 0
3 years ago
A cylinder has a volume of 83 in3 and is 10 in. tall. What is the radius of the cylinder in inches? Round your answer to the nea
Nataly [62]
To find the radius of the cylinder you will use the volume formula and solve for the radius.

V = pi x r^2 x h
83 = 3.14 x r^2 x 10
83 = 31.4 x r^2; divide both sides by 31.4
r^2 = 2.6; find the square root of 2.6
r = 1.6 in.

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3 0
2 years ago
A recent study from the University of Virginia looked at the effectiveness of an online sleep therapy program in treating insomn
Ludmilka [50]

Answer:

1. The 99% confidence interval for the difference in average is -6.47377 < μ₁ - μ₂ < -11.34623

2. The possible issues in the calculations includes;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

Step-by-step explanation:

1. The number of adults with insomnia in the sample = 45

The number of adults that participated in the therapy, n₁ = 22

The number of candidates that served as control group, n₂ = 23

The average score for the for the 22 participants of the program, \overline x_1 = 6.59

The standard deviation for the 22 participants of the program, s₁ = 4.10

The average score for the for the 23 subjects in the control group, \overline x_2 = 15.50

The standard deviation for the 23 subjects in the control group, s₂ = 5.34

The confidence interval for unknown standard deviation, σ, is given by the following expression;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

α = 1 - 0.99 = 0.01

α/2 = 0.005

The degrees of freedom, df = 22 - 1 = 21

t_{\alpha /2} = t_{0.005, \, 21} = 1.721

Therefore, we have;

\left (6.59- 15.5  \right )\pm1.721 \cdot \sqrt{\dfrac{4.10^{2}}{22}+\dfrac{5.34^{2}}{23}}

The 99% confidence interval for the difference in average is therefore given as follows;

-6.47377 < μ₁ - μ₂ < -11.34623

Therefore, there is considerable evidence that the participants in the survey  had lower average score than the subjects in the control group

2. The possible issues in the calculations are;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

5 0
2 years ago
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