Since we must save 50 meals for volunteers, the real amount we are giving away is 700 meals in 12 hours.
700/12 = 58.3333...
10*58.333.. = 583.333....
Since we can't serve 1/3 of a person, we take 583. Hope this helps!
Multiply the first equation by -2 gives:_
-2y = -8 + 2x
2y = 8 - 2x
adding these 2 equations:-
0 = 0
This shows that the 2 equations are equal so there are infinite solutions
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
No estoy segura e -2 ao quadrado esa es toda la pregunta
Answer: 30 square yards: C
