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marin [14]
4 years ago
15

What is the answer to 0x+2=1x+3 ?

Mathematics
1 answer:
OLga [1]4 years ago
4 0

Answer:

x=-1

Step-by-step explanation:

Okay, First you subtract 0x to the other side:

0x-0x+2=1x-0x+3

2=1x+3

Subtract 3 on the other side:

2-3=1x+3-3

-1=1x

Divide:

\frac{-1}{1} =\frac{1x}{1}

x=-1

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Algebraically solve for x
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<h2>Steps</h2>

So firstly, we have to make all the denominators the same. To do this, we need to find their LCD, or lowest common denominator. In this case, the LCD is gonna be 6(x + 3). With each fraction, multiply the numerator and denominator by the term that will get the denominator to the LCD:

\frac{-3}{x+3}*\frac{6}{6}=\frac{-18}{6(x+3)}\\\\\frac{1}{2}*\frac{3(x+3)}{3(x+3)}=\frac{3(x+3)}{6(x+3)}\\\\\frac{x}{6}*\frac{x+3}{x+3}=\frac{x(x+3)}{6(x+3)}\\\\\frac{-1}{2}*\frac{3(x+3)}{3(x+3)}=\frac{-3(x+3)}{6(x+3)}\\\\\\\\\frac{-18}{6(x+3)}+\frac{3(x+3)}{6(x+3)}=\frac{x(x+3)}{6(x+3)}+\frac{-3(x+3)}{6(x+3)}

Now with all the denominators the same, we can cancel them out by multiplying both sides by 6(x + 3):

-18+3(x+3)=x(x+3)+-3(x+3)

Next, solve the multiplications:

-18+3x+9=x^2+3x-3x-9

Next, combine like terms:

3x-9=x^2-9

Next, subtract both sides by 3x and add both sides by 9:

0=x^2-3x

Next, we want to make the right side of the equation a perfect square. To find the constant of the soon-to-be perfect square, divide the x coefficient by 2 and square the quotient. Add the result onto both sides of the equation:

-3\div 2=-1.5\\(-1.5)^2=2.25\\\\2.25=x^2-3x+2.25

Now, factor the right side:

2.25=(x-1.5)^2

Next, square root both sides of the equation:

\pm\ 1.5=x-1.5

Next, add both sides by 1.5:

1.5\pm 1.5=x

Lastly, solve the left side twice - once with the plus sign and once with the minus sign:

3,0=x

<h2>Answer</h2>

<u>In short, x = 0 and 3.</u>

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