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aliina [53]
3 years ago
15

PLEASE HELP.!! THANK YOUU. accurate answers appreciated:)

Mathematics
1 answer:
Anni [7]3 years ago
5 0

\bf \cfrac{1}{1-sin(x)}+\cfrac{1}{1+sin(x)}=\cfrac{2}{cos^2(x)} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the LCD of [1-sin(x)][1+sin(x)]}}{\cfrac{[1+sin(x)]1~~+~~[1-sin(x)]1}{\underset{\textit{difference of squares}}{[1-sin(x)][1+sin(x)]}}} \\\\\\ \cfrac{1+sin(x)+1-sin(x)}{1^2-sin^2(x)}\implies \cfrac{1+sin(x)+1-sin(x)}{1-sin^2(x)}

recall that 1 - sin²(θ) = cos²(θ).

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Bob and rob in ratio 3:4 and their age 4 years ago was 5:7 find their ages
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Answer:

Present Day:

Bob:Rob:Difference

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4 years ago:

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valentina_108 [34]

Answer:

If the total cost of the 4 necklaces was 18.40 then that means in order to find out how much she spent on pendents she needs to subtract the amount of beads from from the total cost so,

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3 years ago
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Step-by-step explanation:

8 0
3 years ago
Help me please explain
Vera_Pavlovna [14]

Answer:

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Step-by-step explanation:

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I hope this helped! Mark me Brainliest! :) -Raven❤️

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