Question

Sebuah kolom udara memiliki panjang 40cm.Jika garpu kala mempunyai frekuensi 320Hz,maka besarnya cepat rambat gelombang bunyi diudara pada saat resonasi pertama adalah....m/s.

Answer 1

Answer:

Velocity of sound is 512 m/s

Explanation:

for first resonance condition we know that

$\frac{\lambda}{4} = L$

$\frac{\lambda}{4} = 0.40$

$\lambda = 1.6 m$

now the frequency is given as

$f = 320 Hz$

now to find the velocity of sound we have

$v = \lambda f$

$v = 1.6 (320)$

$v = 512 m/s$