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zhannawk [14.2K]
3 years ago
6

A car travels 30 km north in 25 min. and 40 km east in 35 min. What is the total time in hours? Be careful to carry over the pro

per number of significant figures when you convert to hours.
Physics
2 answers:
lapo4ka [179]3 years ago
4 0

Answer:

t = 1.0 hours

Explanation:

as we know that all the data is given here in 2 significant figures

so here we need to find the total time of the motion

that time must be in two significant figures

here we know that

t_1 = 25 min

t_2 = 35 min

so here total time is given as

t = t_1 + t_2

t = 25 + 35

t = 60 min

t = 1.0 hour

inna [77]3 years ago
3 0
25+35=60mins so 1.0 hours
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I have no clue what to do please help.
Yakvenalex [24]

Answer:

Step one : read the directions

Step two: complete the assignment

Explanation:

3 0
2 years ago
Why does it take more force to push a car than it takes to push a bicycle? Please fully explain
never [62]
The car mas more mass than a bicycle. Newton's second law states force equals mass times acceleration.
6 0
3 years ago
The suspension system of a 2100 kg automobile "sags" 8.5 cm when the chassis is placed on it. Also, the oscillation amplitude de
Gennadij [26K]

Answer:

Part a)

k = 6.06 \times 10^4 N/m

Part b)

b = 1795.4 kg/s

Explanation:

Part a)

as the mass of the suspension system is given as

m = 2100 kg

also we have

x = 8.5 cm

so now for force balance we have

mg = kx

(525)(9.81) = k(0.085)

k = 6.06 \times 10^4 N/m

Part b)

Now we know that amplitude decreases by 63% in each cycle

so after one cycle the amplitude will become 37% of initial amplitude

so it is given as

A = 0.37 A_o

also we know

A = A_o e^{-bt/2m}

0.37 A_o = A_o e^{-bt/2m}

\frac{bt}{2m} = 1

b = \frac{2m}{t}

here t = time period of one oscillation

so it is

t = 2\pi\sqrt{\frac{m}{k}}

t = 2\pi\sqrt{\frac{525}{6.06 \times 10^4}}

t = 0.58 s

now damping constant is

b = \frac{2(525)}{0.58}

b = 1795.4 kg/s

7 0
3 years ago
The eyepiece of a compound telescope has a focal length of 12 cm and the objective lens has a focal length of 16 m. What is the
olasank [31]

Answer:

The magnification is 133X

Explanation:

For a refractor telescope using convex lenses, the overall magnification os calculated as by dividing the focal length of the objective by that  of the eyepiece.

M = \frac{f(obj)}{f(eye)}

So:

M = \frac{16 m}{12 cm}

Care must be taken with the units, in this case they are in meters and centimeters, they should be converted into the same unit before calculating:

M = \frac{16 m}{0.12 m} = 133

3 0
3 years ago
A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail
grandymaker [24]
The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

                                 (2 m/s  +  49 m/s)  =  51 m/s .
7 0
2 years ago
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