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Murljashka [212]
3 years ago
10

A 40.0-$kg$ body is moving in the direction of the positive x axis with a speed of 238 $m/s$ when, owing to an internal explosio

n, it breaks into three pieces. One part, whose mass is 7.0 $kg$, moves away from the point of explosion with a speed of 356 $m/s$ along the positive y axis. A second fragment, whose mass is 4.5 $kg$, moves away from the point of explosion with a speed of 357 $m/s$ along the negative x axis. What is the speed of the third fragment
Physics
1 answer:
Julli [10]3 years ago
4 0

Answer:

v_3 = 400\ m/s

Explanation:

given,

mass of the body = 40 Kg

speed in x-axis = 238 m/s

mass break into three part

m₁ = 7 kg

v₁ = 356 m/s (along the positive y axis)

m₂ = 4.5 kg

v₂ = 357 m/s(along the negative x axis)

m₃ = 40 - (7 + 4.5) = 28.5 Kg

v₃ = ?

using conservation of momentum

MV = m₁v₁ + m₂v₂ + m₃v₃

(40)(238) \hat{i} = (7)(356) \hat{j} - (4.5)(357) \hat {i} + 28.5 v_3

(9520) \hat{i} = 2492 \hat{j} - 1606.5\hat {i} + 28.5 v_3

11126.5 \hat{i} - 2492 \hat{j} = 28.5 v_3

v_3 =390.40 \hat{i} - 87.44 \hat{j}

v_3 = \sqrt{390.40^2 + 87.44^2}

v_3 = 400\ m/s

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Water inside a tub rises from 15 mL to 19 mL when an object is submerged. If the mass of the object is 249, what's the density o
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Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

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We have

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A particular cylindrical bucket has a height of 36.0 cm, and the radius of its circular cross-section is 15 cm. The bucket is em
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Answer:

a. 0.000002 m

b. 0.00000182 m

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36 cm = 0.36 m

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a) We can start by calculating the air-water pressure of the bucket submerged 20m below the water surface:

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b) If the temperatures changes, we can still reuse the ideal gas equation above:

\frac{P_1Ah_1}{T_1} = \frac{P_2Ah_2}{T_2}

h_2 = h_1\frac{P_1T_2}{P_2T_1} = 0.36\frac{1.105 * 275}{200000*300} =0.00000182 m

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