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natima [27]
3 years ago
8

I need help please ASAP

Chemistry
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

the name for NO is nitrogen monoxide

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C3H6(OH)2 major species present when dissolved in water
topjm [15]
<span>Answer: the major species present when C₃H₆(OH)₂ is the same molecule.
</span><span />

<span>Explanation:
</span><span />

<span>When solutes dissolve in water there are two possibilities: 1) either the solute dissociate into ions (which is the case of ionic compounds) and the ions are solvated by the solvent, or 2) in the case of covalent compounds the entire molecule is solvated by the molevules of the solvent (water).
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<span>The compound C₃H₆(OH)₂ (propylene glycol) is a covalent compound, so when dissolved in water it will not dissociate but will remain as a molecule, and that molecules is the species solvated by the molecule of water.</span>
6 0
3 years ago
One of the hydroxybenzoic acids is known by the common name salicylic acid. Its methyl ester, methyl salicylate, occurs in oil o
KIM [24]

Answer:

Please see attachment

Explanation:

Please see attachment

8 0
3 years ago
What effect does increasing the concentration of a dissolved solute have on each of the colligative properties?
Igoryamba

Answer:

If we increase the concentration of a dissolved solute, the solution would have a vapor pressure so much low, the boiling temperature for the solution will be so high, freezing point for the solution will be so much low and the osmotic pressure will be higher.

Colligative properties always depends on dissolved particles (solute)

Explanation:

These are the colligative properties

- Vapor pressure lowering

ΔP = P° . Xm

Vapor pressure of pure solvent - Vapor pressure of solution.

If we add more solute, it would raise the Xm, so the solution would have a vapor pressure so much low.

Vapor pressure pure solvent - Vapor pressure solution ↑ = P° . Xm ↑

- Boiling point elevation

ΔT = Kb . m

When we add more solute, we are increasing the molality.

↑T° boiling of solution - T° boiling pure solvent = Kf . m ↑

Boiling temperature for the solution will be so high.

- Freezing point depression

When we add more solute, we are increasing the molality.

ΔT = Kf . m

T° fussion of pure solvent - ↓T° fussion of solution = Kf . m↑

Freezing point for the solution will be so much low.

- Osmotic pressure

π = M . R . T

When we add solute, molarity is increasing. Therefore the osmotic pressure will be higher.

π↑ = M↑ . R . T

7 0
4 years ago
A Canadian dime weighs 1.75g and has a thickness of 1.22mm. A Canadian quarter weighs 4.4g and has a thickness of 1.58mm. You ha
balu736 [363]

The mass of the total number of coins is 1405 g.

Since the thickness of each dime is 1.22 mm and we have each pile being 61.0 mm tall, we need to determine the number of dimes in each pile by dividing the height of the pile by the thickness of each dime.

so, number of dimes in each pile = height of each pile/thickness of each dime = 61.0 mm/1.22 mm = 50 dimes.

Since we have 6 piles, the total number of dimes in all the piles is 6 piles × 50 dimes/pile = 300 dimes.

So, there are 300 dimes in the 6 piles.

Since each dime weighs 1.75 g, 300 dimes will weigh 1.75 g/dime × 300 dimes = 525 g.

In the pile of quarters, we have $ 50 worth of quarters.

Since each quarter = $ 0.25, the number of quarters in that pile is total worth of quarter/value of one quarter = $ 50/$ 0.25 = 200 quarters.

Since each quarter weighs 4.4 g, 200 quarters will weigh 4.4 g/quarter × 200 quarters = 880 g

So, the mass of the total number of coins = total mass of dimes + total mass of quarters = 525 g + 880 g = 1405 g

So,  the mass of the total number of coins is 1405 g.

Learn more about mass of coin here:

brainly.com/question/19194652

5 0
3 years ago
BRAINLIEST IF EXPLANATION IS GIVEN AND ANSWER IS CORRECT:
Volgvan

Answer:

Q = 2997.69 J

Explanation:

Given that,

The mass of ice, m = 15.6 grams

The temperature increases from -8.76 degrees Celsius to 85.9 degrees Celsius.

The specifc heat of ice is 2.03 J/g°C

We need to find the amount of energy required. The formula for energy required is given by :

Q=mc\Delta T\\\\=15.6\times 2.03\times (85.9-(-8.76))\\\\=2997.69\ J

So, the required heat is equal to 2997.69 J.

7 0
3 years ago
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