Answer:
1) 0.0025 mol/L.s.
2) 0.0025 mol/L.s.
Explanation:
<em>H₂ + Cl₂ → 2HCl.</em>
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<em>The average reaction rate = - Δ[H₂]/Δt = - Δ[Cl₂]/Δt = 1/2 Δ[HCl]/Δt</em>
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<em>1. Calculate the average reaction rate expressed in moles H₂ consumed per liter per second.</em>
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The average reaction rate expressed in moles H₂ consumed per liter per second = - Δ[H₂]/Δt = - (0.02 M - 0.03 M)/(4.0 s) = 0.0025 mol/L.s.
<em>2. Calculate the average reaction rate expressed in moles CI₂ consumed per liter per second.</em>
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The average reaction rate expressed in moles Cl₂ consumed per liter per second = - Δ[Cl₂]/Δt = - (0.04 M - 0.05 M)/(4.0 s) = 0.0025 mol/L.s.
Answer:
ITS THE LAST ONE AND THE SECOND ONE
Explanation:
Answer : Option E) 50 grams.
Explanation : According to the solubility curves the compound
to dissolve at 50 °C in 100 mL of water will need 50 grams of the compound. It is clearly indicated in the graph which is marked with red that at 50°C approximately 50.4 grams of the compound
will be needed to dissolved in 100 mL of water to form a solution.
36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose
find molarity
0.200 moles of glucose / 2 liters = 0.100 molar solution
(hope this helps)
Answer: Option C) 4 moles
Explanation:
The reaction below shows the decomposition of 2 moles of water to yeild 2 moles of hydrogen and 1 mole of oxygen respectively.
2H2O(l) --> 2H2(g) + O2 (g)
So, if 2 moles of H2O produce 1 mole of O2
8 moles of H2O will produce Z mole of O2
To get the value of Z, cross multiply
2 x Z = 1 x 8
2Z = 8
Z = 8/2
Z = 4
Thus, 4 moles of O2 is produced from the complete decomposition of 8 moles H2O .