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2 years ago

Why do convection currents occur?

Chemistry

1 answer:

Maurinko [17]2 years ago

6 0

Answer:

Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.

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A sample of nitrogen gas had a volume of 500. ml, a pressure in its closed container of 740 torr and a temperature 25 degrees c

Semenov [28]

Question:
<span>A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?

Answer:

Data Given:
V</span>₁ = 500 mL

P₁ = 740 torr

T₁ = 25 °C + 273 = 298 K

V₂ = ?

P₂ = 760 torr

T₂ = 50 °C + 273 = 323 K

Solution:
Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,

P₁ V₁ / T₁ = P₂ V₂ / T₂

Solving for V₂,

V₂ = (P₁ V₁ T₂) ÷ (T₁ P₂)

Putting Values,

V₂ = (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)

V₂ = 527.68 mL

7 0

2 years ago

A blacksmith melts and shapes a block of iron into a blade. She then sets the blade, whose edges are molten, outside, where it i

Margaret [11]

The answer is C due to the rain making contact with the iron it creates moisture which cause the iron to begin oxidizing which causes the iron to rust which is a chemical reaction then the blade which was once malleable because it was heat becomes harden and rust is created as I said before the physical aspect of the iron chances due to rust developing on it it's no longer has the luster it once had

4 0

2 years ago

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One mechanism for the synthesis of ammonia proposes that N₂ and H₂ molecules catalytically dissociate into atoms:N₂ ⇆ 2N(g) log

Pavlova-9 [17]

The artificial fixation of nitrogen (N2) has enormous energy, environmental, and societal impact, the most important of which is the synthesis of ammonia (NH3) for fertilizers that help support nearly half of the world's population.

<h3>Artificial fixation of nitrogen</h3>

a) The equilibrium constant expression is Kp=PCH4 PH2 OP CO×PH 23.

(b) (i) As the pressure increases, the equilibrium will shift to the left so that less number of moles are produced.

(ii) For an exothermic reaction, with the increase in temperature, the equilibrium will shift in the backward direction.

(iii) When a catalyst is used, the equilibrium is not disturbed. The equilibrium is quickly attained

To learn more about equilibrium constant visit the link

brainly.com/question/10038290

#SPJ4

6 0

1 year ago

This <br> Question please

Marizza181 [45]

Answer:

See detailed explanation.

Explanation:

Hello!

i. In this case, since the given chemical reaction is exothermic due to the negative change in the enthalpy of reaction, we infer that according to the mentioned principle, by lowering the temperature the reaction will shift rightwards and therefore the yield is increased; thus, you need a lower temperature than the specified.

ii. In this case, since the reaction has less moles at the products side, according to the mentioned principle it'd be necessary to rise the pressure in order to increase the yield, since the increase of pressure favors the reaction side with the fewest number of moles.

Best regards!

4 0

2 years ago

Which solute would be more effective at lowering the freezing point of water: MgCl2 and KNO3? Explain.

Phantasy [73]

Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

The depression in freezing point (ΔTf) can be calculated using the relation:

ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kf is the molal depression constant of water.

m is the molality of the solution (m = 1.0 m, for all solutions).

(1) NaCl:

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(2) MgCl₂:

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

∴ ΔTb for (MgCl₂) = i.Kb.m = (3)(Kf)(1.0 m) = 3(Kf).

(3) NaCl:

i for KBr = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (KBr) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(4) AlCl₃:

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

So, the ionic compound will lower the freezing point the most is: AlCl₃

4 0

2 years ago

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