Question

A box of mass 13kg sits on a table with a coefficient of static friction of 0.85. What is the maximum force of static friction?

Answer 1

Answer:

108.3 N

Explanation:

The maximum force of static friction acting on the box is given by:

$F=\mu N$

where

$\mu = 0.85$ is the coefficient of static friction

N is the normal reaction of the table on the box

Since the box is in equilibrium along the vertical direction, the normal reaction N is equal to the weight of the box, so:

$N=mg=(13 kg)(9.8 m/s^2)=127.4 N$

And so, the maximum force of static friction is

$F=(0.85)(127.4 N)=108.3 N$